50. Ages of College Students An admissions director wants to estimate the mean age of all students enrolled at a college. The estimate must be within 1.5 years of the population mean. Assume the population of ages is normally distributed. a. Determine the minimum sample size required to construct a 90% confidence interval for the population mean. Assume the population standard deviation is 1.6 years. b. The sample mean is 20 years of age. Using the minimum sample size with a 90% level of confidence, does it seem likely that the population mean could be within 7% of the sample mean? within 8% of the sample mean? Explain.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
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50. Ages of College Students An admissions director wants to estimate the mean age of all
students enrolled at a college. The estimate must be within 1.5 years of the population
mean. Assume the population of ages is normally distributed.
a. Determine the minimum sample size required to construct a 90% confidence interval
for the population mean. Assume the population standard deviation is 1.6 years.
b. The sample mean is 20 years of age. Using the minimum sample size with a 90%
level of confidence, does it seem likely that the population mean could be within 7%
of the sample mean? within 8% of the sample mean? Explain.
Transcribed Image Text:50. Ages of College Students An admissions director wants to estimate the mean age of all students enrolled at a college. The estimate must be within 1.5 years of the population mean. Assume the population of ages is normally distributed. a. Determine the minimum sample size required to construct a 90% confidence interval for the population mean. Assume the population standard deviation is 1.6 years. b. The sample mean is 20 years of age. Using the minimum sample size with a 90% level of confidence, does it seem likely that the population mean could be within 7% of the sample mean? within 8% of the sample mean? Explain.
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