50.00 mL of 0.1000 M Ti2+ solution is titrated with 0.1000 M Sn4+ solution. Find the concentration of the Ti2+ solution at the equivalence point. K= 4.7x1017 2 Ti2+ + Sn4+ ↔ 2 Ti3+ + Sn2+

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Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.91QP: A 50.0-mL sample of a 0.100 M solution of NaCN is titrated by 0.200 M HCl. Kb for CN is 2.0 105....
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50.00 mL of 0.1000 M Ti2+ solution is titrated with 0.1000 M Sn4+ solution. Find the concentration of the Ti2+ solution at the equivalence point. K= 4.7x1017

2 Ti2+ + Sn4+ ↔ 2 Ti3+ + Sn2+

  • A. 

    8,6 x 10-8 M

  •  B. 

    0,033 M

  •  C. 

    0,0667 M

  •  D. 

    4,3 x10-8 M

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