6. [#446] Going up, going down (part E) m M = 2m We how have: Net force on m Net force on M ma = T-mg Ma = Mg - T Using these results from part D, find a very simple expression for the acceleration a in terms of g.

6. [#446] Going up, going down (part E) m M = 2m We how have: Net force on m Net force on M ma = T-mg Ma = Mg - T Using these results from part D, find a very simple expression for the acceleration a in terms of g.

Name: 6. [#446] Going up, going down (part E)M =2mWe how have:Net force on
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Description: 6. [#446] Going up, going down (part E)M =2mWe how have:Net force on mNet force on Mma = T-mgMa = Mg-TUsing these results from part D, find a very simple expression for the acceleration a in terms of g.Acceleration =3

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter2: Kinematics

Section: Chapter Questions

Problem 25CQ: How many times higher could an astronaut jump on the Moon than on Earth if his takeoff speed is the...

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