6. Write a program in Python that will generate the following series using any looping statement: 4. 32 256 4. 2 4 8. 2 8. 32 Correct the errors and convert the following while loop to for loop. z-0 n=float(int(input( “Enter number") i=5 while i
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A: The question is on what is the value of AL after execution.
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A: By analyzing the given program, we can say that :
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- Program in JAVA using While Loop Write a program that takes a positive integer input and prints the numbers starting from input until 0 in one line where each numbers are separated by a space. Note: There's an initial code prepared for you. Go directly to the code editor file and complete the solution. Input 1. A positive integer input Output Enter a number: 5 5 4 3 2 1 0Create a class NestedForPatternB. Use nested for-loops that display the following pattern:Write a program that grades arithmetic quizzes as follows: (Use the below startup code for Quizzes.java and provide code as indicated) Ask the user how many questions are in the quiz. Use a for loop to load the array. Ask the user to enter the key (that is, the correct answers). There should be one answer for each question in the quiz, and each answer should be an integer. They can be entered on a single line, e.g., 34, 7, 13, 100, 8 might be the key for a 5-question quiz. You will need to store the key in an array called “key”. Ask the user to enter the student’s answers for the quiz to be graded. There needs to be one answer for each question. Note that each answer can simply be compared to the key as it is entered. If the answer is correct, add 1 to a correct answer counter. Do this in a separate for loop from the loop used to load the array. When the user has entered all of the answers to be graded, print the number correct and the percent correct. When this works, nest your for…
- int i=0; while(i<10) { printf(“I am inside the loop”); } What is wrong with this block of C code? Mark the errors and fix them.def apply_gaussian_noise(X, sigma=0.1): """ adds noise from standard normal distribution with standard deviation sigma :param X: image tensor of shape [batch, 3, height, width] Returns X + noise. """ ### YOUR CODE HERE ### # noise tests theoretical_std = (X_train[:100].std() ** 2 + 0.5 ** 2) ** .5 our_std = apply_gaussian_noise(X_train[:100], sigma=0.5).std() assert abs(theoretical_std - our_std) < 0.01, \ "Standard deviation does not match it's required value. Make sure you use sigma as std." assert abs(apply_gaussian_noise(X_train[:100], sigma=0.5).mean() - X_train[:100].mean()) < 0.01, \ "Mean has changed. Please add zero-mean noise"Write a C#program that displays the pattern show in the* sample executable.** Type of loop-> your favorite (you must use a pair of* nested loops)* Hints:* 1) Use variables that increments* 2) When running the sample, use values between 61 and* 76 for the number of columns, values between 16 and* 21 the number of rows* 3) Start with a rectangular array of "X" then figure out* how to create one of the upward lines and then the* backwards lines and then both lines*
- The Fibonacci sequence is a famous sequence in mathematics. The first element in the sequence is 0 and the second element is 1. The nth element is defined as Fn = Fn-1 + Fn-2- Implement the fib function, which takes an integer n and returns the n th Fibonacci number. Use a while loop in your solution. def fib(n): """Returns the nth Fibonacci number. >>> fib (0) 0 >>> fib (1) 1 >>> fib(2) 1 >>> fib(3) 2 >>> fib(4) 3 >>> fib(5) 5 >>> fib(6) 8 >>> fib (100) 354224848179261915075 "*** YOUR CODE HERE ***"Use a for loop to modify each element of arrfile4 by 2Use a for loop to modify each element of arrfile4a by 3 write the new contents of arrfile4 to file4by2write the new contents of arrfile4a to file4aby3 CODE: import java.util.*; import java.io.*; public class Pwriter2 { public static void main(String[] args) throws IOException { PrintWriter tofile2 = new PrintWriter ("file4.txt"); PrintWriter tofile2A = new PrintWriter ("file4a.txt"); int[] arrfile4=new int [10]; int[] arrfile4a=new int [10]; int i=0; while(i<10) { arrfile4[i]=i+1 ; tofile2.println(arrfile4[i] ); arrfile4a[i]=i+11; tofile2A.println(arrfile4a[i]); i=i+1; } tofile2.close(); tofile2A.close(); } }Implement using python progeam 1) The Variables used here are as followes B : True if there is a Baseball Game on TV, False if not G: True if George watches TV, False if not C: True if George is out of Cat Food, False if not F: True if George feeds his cat, False if not. Let us say you are given some Training Data which represents what happens over a period of time (For example: This file contains what happens every evening over one specific year). Your Task is to learn the conditonal probabilty tables for the bayesian network from the training data. The training data will be formatted as follows: The first number is 0 if there is no baseball game on TV (B is false), and 1 if there is a baseball game on TV (B is true). The second number is 0 if George does not watch TV (G is false), and 1 if George watches TV (G is true). The third number is 0 if George is not out of cat food (C is false), and 1 if George is out of cat food (C is true). The fourth number is 0 if George does not feed…
- JAVA CODE PLEASE Functions With No Parameters and Return Values Quiz by CodeChum Admin Create a function named banner that prints “CodyChum” with a newline. In the main function, write a program that accepts an integer input which would serve as an inclusive stopping point of a loop iteration that starts at the value of 1. If the number that loops through the range is divisible by either 2 or 3, then call the banner function, otherwise just print the number. Input 1. One line containing an integer Output First line is the integer user input. Succeeding multiple lines containing an integer or “CodyChum” 10 1 CodyChum CodyChum CodyChum 5 CodyChum 7 CodyChum CodyChum CodyChumIn c++ Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, th backwards. End each loop with a newline. Ex: If courseGrades (7, 9, 11, 10), print: - 7 9 11 10 10 11 9 7 Hint Use two for loops. Second loop starts with i=NUM VALS-1. (Notes) Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]) See How to Use zyBooks" Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message 2 using namespace std; 3 4 int main() { 5 6 7 8 9 10 11 12 13 14 const int NUM VALS-4; int courseGrades [NUM VALS]; int i; for (i-8; 1 NUM VALS; ++) { cin>> courseGrades[1]; } Your solution goes…ntegers outerRange and innerRange are read from input. Complete the outer while loop so the inner loop executes (outerRange + 1) * innerRange times. Ex: If the input is 6 5, then the output is: Inner loop ran 35 times import java.util.Scanner; public class LoopCounter { public static void main (String[] args) { Scanner scnr = new Scanner(System.in); int outerRange; int innerRange; int count; int i; int j; outerRange = scnr.nextInt(); innerRange = scnr.nextInt(); count = 0; i = 0; while (/* Your code goes here */) { j = 0; while (j < innerRange) { ++count; ++j; } ++i; } System.out.println("Inner loop ran " + count + " times"); } }