7. The compounds shown are possible acylation products from 1,2,4-trimethylben- zene (pseudocumene). Explain the only way you could distinguish these two prod- ucts by NMR spectroscopy. CH3 CH3 CH3 CH3 CH3 CH3 CH3 CH3
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- Reaction of p-cresol with two equivalents of 2-methylprop-1-ene affordsBHT, a preservative with molecular formula C15H24O. BHT gives thefollowing 1H NMR spectral data: 1.4 (singlet, 18 H), 2.27 (singlet, 3 H), 5.0(singlet, 1 H), and 7.0 (singlet, 2 H) ppm. What is the structure of BHT?Draw a stepwise mechanism illustrating how it is formed.Following is the structure of miconazole, the active antifungal agent in a number of over-the-counter preparations, including Monistat, that are used to treat vaginal yeast infections. One of the compounds needed for the synthesis of miconazole is the trichloro derivative of toluene shown on its right. (a) Show how this derivative can be synthesized from toluene. (b) How many stereoisomers are possible for miconazole?When acetonitrile is treated with concentrated sulfuric acid and tert-butanol, followed by water, a product is formed whose 'H NMR spectrum exhibits the following three signals: singlet, 1.3 ppm, 9 H; singlet, 2.0 ppm, 3 H; and broad singlet, 8.2 ppm, 1 H. Its IR spectrum exhibits one broad absorption of medium intensity between 3300 and 3500 cm-1, and a narrow, intense absorption near 1650 cm¯1. A key intermediate is shown. Draw the structure of the product, and draw the complete, detailed mechanism for the reaction. CH3 CH3 H2SO4 (conc) H2O ? + H3C H3C H3C-C=Ñ-c `CH3 CH3 HO
- Identify products A and B from the given 1H NMR data. Treatment of CH2=CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A?Identify products A and B from the given 1H NMR data. Treatment of acetone [(CH3)2C=O] with dilute aqueous base forms B. Compound B exhibits four singlets in its 1H NMR spectrum at 1.3 (6 H), 2.2 (3 H), 2.5 (2 H), and 3.8 (1H) ppm. What is the structure of B?Identify the following compound from its IR and proton NMR spectra. C,H1,0: 'H NMR 8 3.31 (3H, s); 8 2.41 (1H, s); & 1.43 (6H, s) IR: 2110, 3300 cm-1 (sharp) Draw the compound.
- Propose a structure for a C,H150,N compound that is unstable in aqueous acid and has the given NMR spectra. 'H NMR: 8 2.30 (6H, s); 8 2.45 (2H, d, J = 6 Hz); 8 3.27 (6H, s); 8 4.50 (1H, t, J = 6 Hz) 13C NMR: 8 46.3, 8 53.2, 8 68.8, 8 102.4 Draw C,H1502N. Select Draw Rings More C N APR étv N Aa MacBook AirIdentify products A and B from the given 1H NMR data.a. Treatment of CH2 = CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3 H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A?b. Treatment of acetone [(CH3)2C = O] with dilute aqueous base forms B. Compound B exhibits four singlets in its 1H NMR spectrum at 1.3 (6 H), 2.2 (3 H), 2.5 (2 H), and 3.8 (1 H) ppm. What is the structure of B?For following substituted benzenes: [1] C6H5Br; [2] C6H5CN; [3] C6H5OCOCH3: Does the substituent activate or deactivate the benzene ring inelectrophilic aromatic substitution?
- 9a) The proton bonded to the carbon adjacent to the carbonyl group in the following compound can be classified into which chemical shift in the ¹H-NMR spectra of aldehydes and ketones? R or H H - 10.0-12.0 ppm R H -2.0-3.0 ppm NO₂ N (1) 9b) Choose the one below that could be resolved into enantiomers. (1) alpha hydrogens = ? ppm NO₂ NO₂ 9c) Which of the following is the major product of the reaction below. `N H -5.0-7.0 ppm (11) (11) -0.0-1.0 ppm HNO3, H₂SO4 H NO₂ (III) NO₂ (1) and (II) (IV) None of the options (IV)A compound with molecular formula C5H10Br2 displays the following 13C NMR along with the DEPT-90 and DEPT-135 13CNMR spectra. What is the structure for this compound?gas, Cl¬CH2CH2¬S¬CH2CH2¬Cl, was used as a poisonous chemical agentin World War I. Mustard gas is much more toxic than a typical primary alkyl chloride. Itstoxicity stems from its ability to alkylate amino groups on important metabolic enzymes,rendering the enzymes inactive.(a) Propose a mechanism to explain why mustard gas is an exceptionally potent alkylatingagent.(b) Bleach (sodium hypochlorite, NaOCl, a strong oxidizing agent) neutralizes and inactivates mustard gas. Bleach is also effective on organic stains because it oxidizes coloredcompounds to colorless compounds. Propose products that might be formed by thereaction of mustard gas with bleach.