711 Search closet Complete the following function according to its docstring using a for loop. String method startswith may come in handy here. The lists we test will not all be shown; instead, some will be described in English. If you fail any test cases, you will need to read the description and make your own test. 1 from typing import List 2 3 4 5 678 9 10 11 12 13 14 15 16 17 18 19 20 def search_closet (items: List[str], colour: str) -> List[str]: """items is a list containing descriptions of the contents of a closet where every description has the form 'colour item', where each colour is one word and each item is one or more word. For example: shoes', ['grey summer jacket', 'orange spring jacket', 'red green hat'] 1 colour is a colour that is being searched for in items. Return a list containing only the items that match the colour. >>> search_closet(['red summer jacket', 'orange spring jacket', 'red shoes', 'green hat'], 'red') ['red summer jacket', 'red shoes'] >>> search_closet ( ['red shirt', 'green pants'], 'blue') [] >>> search_closet([], 'mauve') [] 111111

711 Search closet Complete the following function according to its docstring using a for loop. String method startswith may come in handy here. The lists we test will not all be shown; instead, some will be described in English. If you fail any test cases, you will need to read the description and make your own test. 1 from typing import List 2 3 4 5 678 9 10 11 12 13 14 15 16 17 18 19 20 def search_closet (items: List[str], colour: str) -> List[str]: """items is a list containing descriptions of the contents of a closet where every description has the form 'colour item', where each colour is one word and each item is one or more word. For example: shoes', ['grey summer jacket', 'orange spring jacket', 'red green hat'] 1 colour is a colour that is being searched for in items. Return a list containing only the items that match the colour. >>> search_closet(['red summer jacket', 'orange spring jacket', 'red shoes', 'green hat'], 'red') ['red summer jacket', 'red shoes'] >>> search_closet ( ['red shirt', 'green pants'], 'blue') [] >>> search_closet([], 'mauve') [] 111111

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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In python, The function count_contains_x takes a list of strings (wordList) and returns the count of how many strings in the list contain at least one upper- or lower-case 'x'. Hint: Use the accumulator pattern to accumulate the count. Hint: You might want to use the string method count. For example: Test Result strlist = ["xerox", "OXEN", "whiffleball", "XOXOX"] print(count_contains_x(strlist)) 3 fish = ["angel", "gold", "cat", "puffer", "damsel"] print(count_contains_x(fish)) 0 strlist = ["X", "x"] print(count_contains_x(strlist)) 2 list_of_one_x = ["x"] print(count_contains_x(list_of_one_x)) 1
Baby Names: Each year, the government releases a list of the 10,000 most common baby namesand their frequencies (the number of babies with that name). The only problem with this is thatsome names have multiple spellings. For example, "John" and ''.Jon" are essentially the same namebut would be listed separately in the list. Given two lists, one of names/frequencies and the otherof pairs of equivalent names, write an algorithm to print a new list of the true frequency of eachname. Note that if John and Jon are synonyms, and Jon and Johnny are synonyms, then John andJohnny are synonyms. (It is both transitive and symmetric.) In the final list, any name can be usedas the "real" name.EXAMPLEInput:Names: John (15), Jon (12), Chris (13), Kris (4), Christopher (19)Synonyms: (Jon, John), (John, Johnny), (Chris, Kris), (Chris, Christopher)Output: John (27), Kris (36)
from surround import surround inputs = [] [] answers = L = ["tank", "godzilla", "tank"] ["tank"] inputs.append (L) answers.append(a) a = TESTS len(inputs) passed = 0 for i in range(TESTS): try: result = surround (inputs[i]) if result not in answers[i]: print("Error found for input: " + str(inputs[i])) else: passed += 1 except Exception: pass result = "Tests passed: + str(passed) + "/" + str(TESTS) print(result)
Allow student to insert one arbitrary string. Save the letters of the string into a list. Design and perform the following tasks and display your results: • Summarizing letters in a string. Write a function that receives a string and returns a list of tuples containing the unique letters and their frequencies in the string. Test your function and display each letter with its frequency. Your function should ignore case sensitivity (that is, 'a' and 'A' are the same) and ignore spaces and punctuation. When done, write a statement that says whether the string has all the letters of the alphabet. • Present descriptive statistics and graphs about the string data. • Sorting letters in different order and removing duplicates • Write a code that produces anagrams of a given string. An anagram of a string is another string formed by rearranging the letters in the first. program must accept inputs from a user, performs an operation using a userdefined function which will accept parameters and…
LAB RESTRICTIONS, PLEASE READ: Do not add any imports, the ones that you need will be given to you. You may not use any dictionaries or dictionary methods. Do not use try-except statements, you should be able to anticipate or prevent any errors from happening at all!
in python Create a corporate B.S. Generator similar to the following Link: http://www.atrixnet.com/bs-generator.html (Links to an external site.) (Links to an external site.) You must create a loop the runs until the user decides to exit. You will need to import this list aAdverbs = ['appropriately','assertively','authoritatively','collaboratively','compellingly','competently','completely','continually','conveniently','credibly','distinctively','dramatically','dynamically','efficiently','energistically','enthusiastically','uniquely'] aAdjectives = ['accurate','adaptive','alternative','backend','user-centric','user friendly','value-added','vertical','viral','virtual','visionary','web-enabled','wireless','world-class','worldwide'] aVerbs = ['actualize','administrate','aggregate','architect','benchmark','brand','build','cloudify','communicate','conceptualize','coordinate','create','cultivate','unleash','utilize','visualize','whiteboard'] aNouns = ['action…
Write the following function that tests whether the list has four consecutive numbers with the same value: def isConsecutiveFour(values):Write a test program that prompts the user to enter a series of integers and reports whether the series contains four consecutive numbers with the same value.
The for loop iterates across the elements in a given list. So long as there are objects to process, it will keep going. In what way does this statement hold true or false?
Create a Flowchart for this code. import random #Define a function to pick 5 numbers from 1 to 38 def getNJCash5lottery_numbers(): #Return the list return random.sample(range(1, 39), 5) def playNJCash5lottery(): #Call the method and assign the list to variable lottery_number = getNJCash5lottery_numbers() print("These are the cash 5 numbers."), #Iterate over list elements for number in lottery_number: #Print the number on one line print(number) #Define a function def main(): while(True): #Call the method to print the list elements playNJCash5lottery() #Prompt the user if they want to play again decide = input("\nDo you want to play again? Yes/No : ") #If they entered "no " or "No" if decide.lower() == "no": #Exit break #Call the "main()" function if __name__ == "__main__": main()
The for loop iterates across the elements in a given list. Hence, it runs forever, provided there are still objects to process. Will this prove to be a true or untrue statement?
Thank you! but for nextTweet and removeTweet. can u rewrite base on the specs: public String nextTweet() Returns the next tweet from the tweet list. If all the tweets in the list are exhausted, cycle around to the start of the list. For example, the following code snippet should produce the output in the comments. Suppose that tweets stores a list of Tweets ["A tweet about something controversial", "Remember to vote!", "Look at this meme :O"]. TweetBotbot=newTweetBot(tweets); System.out.println(bot.nextTweet()); // A tweet about something controversial System.out.println(bot.nextTweet()); // Remember to vote! System.out.println(bot.nextTweet()); // Look at this meme :O System.out.println(bot.nextTweet()); // A tweet about something controversial Think about how to get the next tweet from the list of tweets, and how you can cycle around to the start once you've gone through all the tweets! One Special Case! As you're working on your TweetBot and testing your implementation,…
QUESTION 4 This is a MULTIPLE ANSWER question, which means you are able to select one or more answers as being correct. Note that this does not necessarily mean that there are multiple correct answers. In any case, select all the answers you believe are correct. (NB: There are no part marks awarded for multiple answer questions.) There is a non-empty Python list of integers called numbera whose values are all in the range -maxaize to maxaize, inclusive. The following piece of code causes the SMALLEST value in list numbers to be stored in the variable answer: best - maxsize t a very large integer for number in numbers: if number number: t a very large integer best = number answer = best + a very small integer best - -maxsize for number in numbers: if best best: best = number answer= best best = -maxsize * a very small integer for number in numbers: if best > number: best - number answer best