8. Given the following data for the number of defects per spool of cable, using three-sigma limits, is the process in control? OBSERVATION 1 3 4 6 7 8 9 10 11 12 13 14 Number of defects 2 1 0 1 3 2 0 2 1 3 1 2 0
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- Factors for Computing Control Chart Limits (3 sigma) Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: Day Mean x (mm) Range R (mm) 1 156.9 4.2 2 153.2 4.6 3 153.6 4.1 4 155.5 5.0 5 156.6 4.5 Part 4 c) What are the (UCLx) and (LCLx) using 3-sigma? (UCLx) = mm (round your response to two decimal places). (LCLx) = mmWe want to determine the AOQ for an acceptance samplingplan when the quality of the incoming lots in percent defectiveis 1.5%, and then again when the incoming percent defective is 5%.T he sample size is 80 units for a lot size of 550 units. Furthermore,Pa at 1.5% defective levels is 0.95. At 5% incoming defective levels,the Pa is found to be 0.5. Determine the average outgoing qualityfor both incoming percent defective levels.Lower Range, Sample Size, n Mean Factor, Upper Range, DA A2 D3 2 1.880 3.268 3 1.023 2.574 4 0.729 2.282 5 0.577 2.115 6 0.483 2.004 7 0.419 1.924 0.076 8 0.373 1.864 0.136 0.337 1.816 0.184 10 0.308 1.777 0.223 12 0.266 1.716 0.284
- Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 5 pistons produced each day, the mean and the range of this diameter have been as follows: Day Mean (mm) Range R (mm) 158 4.3 151.2 4.4 155.7 4.2 153.5 4.8 156.6 4.5 What is the UCL using 3-sigma?(round your response to two decimal places). 1. 2. 4.Refer to Table S6.1 - Factors for Computing Control Chart Limits (3 sigma) for this problem. Sampling 4 pieces of precision-cut wire (to be used in computer assembly) every hour for the past 24 hours has produced the following results: Hour Hour Hour R Hour R. 3.25" 0.65 3.05" 0.58" 13 3.01" 0.80" 19 3.41" 1.61" 2 3.10 1.23 8. 2.55 1.13 14 2.83 1.31 20 2.99 1.14 3 3.22 1.48 3.22 21 2.65 1.13 9, 2.85 3.12 0.71 15 1.11 4. 3.39 1.21 10 1.28 16 2.74 0.50 22 3.18 0.41 1.63 1.02 2.97 1.12 17 23 3.04 11 12 2.93 1.17 2.76 1.48 6. 2.86 0.37 3.07 0.45 18 2.84 1.24 24 2.74 Based on the sampling done, the control limits for 3-sigma x chart are (round all intermediate calculations to three decimal places before proceeding with further calculations): Upper Control Limit (UCL-)= inches (round your response to three decimal places). %3D Lower Control Limit (LCL-)= inches (round your response to three decimal places). %3D Based on the x-chart, the wire cutting process has been The control limits for…A control chart for fraction nonconforming is to be established using a center line of p=0.03. What sample size is required if we wish to detect a shift in the process fraction nonconforming to 0.08 with probability 0.50? 1269 475 73 316 216 2 105 150 265
- For 50 consecutive days, a process engineer has measured the weight of acomponent after it has been coated with a special paint. Each day, she takes a sampleof 10 components. The average across all 500 components (50 days, 10 componentsper day) is 45.343018 grams. The standard deviation across all parts is 0.0076382 gram.When constructing an X-bar chart, what would be the center line and what would be thelines for the upper and lower control limits?Refer to Table S6.1 - Factors for Computing Control Chart Limits (3 sigma) LOADING... for this problem. Thirty-five samples of size 7 each were taken from a fertilizer-bag-filling machine at Panos Kouvelis Lifelong Lawn Ltd. The results were: Overall mean = 60.75 lb.; Average range R = 1.64 lb. a) For the given sample size, the control limits for 3-sigma x chart are: Upper Control Limit (UCLx) = nothing lb. (round your response to three decimal places).6-9. A process that produces computer chips has a mean of .04 defective chip and a standard deviation of .003 chip. The allowable variation is from .03 to .05 defective. (a) Compute the capability index for the process (b) Is the process capable?
- Refer to Table S6.1 - Factors for Computing Control Chart Limits (3 sigma) LOADING... for this problem. Sampling 4 pieces of precision-cut wire (to be used in computer assembly) every hour for the past 24 hours has produced the following results: Hour x R Hour x R Hour x R Hour x R 1 3.15" 0.65" 7 3.15" 0.58" 13 3.11" 0.85" 19 4.51" 1.66" 2 3.00 1.23 8 2.65 1.13 14 2.93 1.31 20 2.89 1.04 3 3.22 1.43 9 3.02 0.66 15 3.22 1.11 21 2.55 1.08 4 3.39 1.21 10 2.85 1.28 16 2.84 0.55 22 3.28 0.41 5 3.07 1.12 11 2.73 1.12 17 2.96 1.43 23 2.84 1.63 6 2.76 0.42 12 3.07 0.45 18 2.84 1.34 24 2.64 0.92 Based on the sampling done,…Using samples of 197 credit card statements, an auditor found the following: Sample 1 3 errors Sample 2 3 errors Sample 3 5 errors Sample 4 9 errors 1. what alpha risk would control limits of .0470 and .0038 provide? 2. Using control limits of .0470 and .0038, is the process in control? 3. Construct a control chart for the process, assuming a fraction defective of 2 percent, using two-sigma control limits. Is the process in control?Management at Webster Chemical Company is concerned as to whether caulking tubes are being properly capped. If a significant proportion of the tubes are not being sealed, Webster is placing its customers in a messy situation. Tubes are packaged in large boxes of 135. Several boxes are inspected, and the following numbers of leaking tubes are found: View an example Sample 1 2 3 Get more help. 4 Tubes 7 7 8 5 1 5 6 7 Calculate p-chart three-sigma control limits to assess whether the capping process is in statistical control. The UCL, equals 1 Sample 8 8 9 10 11 12 13 14 Tubes 7 2 4 8 6 9 MacBook Pro 3 Sample 15 16 17 18 19 20 Total Tubes 8 3 3 5 and the LCL equals (Enter your responses rounded to three decimal places. If your answer for LCL, is negative, enter this value as 0.) 3 6 104 Clear all Check answer O