=9 kg) is resting on top of block 2 (i Block 1 (m1 On a sheet of paper, draw the free body diagrams for block 1 and block 2 using the two-subscript notation from class. After completing the free body diagrams, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component. (Use g = 10 m/s2) %3D
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- The diagram below shows an object of mass m= 20kg being acted upon by a force F=50N at an angle of θ=30o. The coefficient of kinetic friction between the object and the surface is 0.100. a.Draw a Free Body diagram for the object. Be sure to show all forces as well as the reference x,y axis. and Using Newton’s 2nd law, write the force equations for both the x and the y directions. Write these equations in terms of the letters m, F, θ, FN, g, f (little f stands for the friction force). X-direction: _______________________________________________________________ Y-direction:________________________________________________________________ b.Solve for the Normal Force c .Use your answer from part b to find the frictional force. d .Solve for the acceleration of the object. e.If this object was originally moving at 4 m/s, how fast would it be moving after 8 seconds? f .How far will…Three blocks where suspended in the air using massless strings and passing through massless and fixed pulleys as shown. The middle mass mB = 5.00 [kg]. When the system achieved equilibrium, it was found out that a = 60.0° and y = 30.0°. MA α тв mc Draw the free body diagrams of block A, B, and C. Write down Newton's 2nd law along the x and y directions for all three blocks. You must have six equations total.Block 1 (7.5 kg) is resting on the surface of a table. A hand pushes vertically down on block 1 with a force of 240. N.On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component. FORCES on BLOCK 1Weight force on block 1 by Earth: (two-subscript notation)Value = i + j N Normal force on block 1 by Hand: (two-subscript notation)Value = i + j N Normal force on block 1 by Surface: (two-subscript notation)Value = i + j N
- ! DN Required information In the below FBD, the forces are labeled with their magnitudes. ΑΝ CN BN What is the net force? N where A = C = 17.4 and B = D = 13.5.Direction: Illustrate and solve for the following problems. I. Consider a picture frame that hangs on a wall, suppose the Tension 3 (T,) is measured to be (a) 250 N with an angle of 28". (b) 150 N with an angle of 60". What would be the T, and T;? b)I need help with this question. I also don’t know how to draw the free body diagram for this problem
- For the following problem, draw free-body diagrams and solve for the requested unknown. Use g = 9.8 m/s/s. A 0.250-kg rightward moving air track glider decreases its speed from 0.872 m/s to 0.798 m/s over the length of a 1.71-m long air track. Determine the average resistive force acting upon the air track glider. PSYWcs (1) Lab. section 1 rd My courses First Semester 2020/2021 Faculty of Arts and Sciences Physics (1) Lab. section 1 Determine the resultant of two forces if EFx= 40g.wt and EFy=100 g.wt, using method of components Select one: O a. 111.8 g.wt, 63.4° O b. 122.1 g.wt, 55° O c. 107.7 g.wt, 68.2° O d. 116.6 g.wt, 59° O e. 104.4 g.wt, 73.3° page Next pag NEXT ACTIV Jump to.. Physics lab 1 2020-202A horizontal force, F1, and a force F2 acting at an angle of 0 to the horizontal, are applied to a block of mass m. The block is moving to the right at a constant velocity across a rough surface. y F, Use Fk to denote the force of kinetic friction. m Please use the interactive area below to draw the Free Body Diagram for the block. 1 Add Force S Reset All Fn v 90 vx Fg v 270 vx F1 v0 Fk v 180 vx Fn Fk F1 Fg Ftotal,x:0 Ftotal,y: 0 Submit I give up! Hint Feedback
- Find I and J values and please answer all parts of this question 2. Block 1 (m1 = 2 kg) is resting on top of block 2 (m2 = 2 kg) on the surface of a table. On a sheet of paper, draw the free body diagrams for block 1 and block 2 using the two-subscript notation from class. After completing the free body diagrams, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component. (Use g = 10 m/s2) FORCES on BLOCK 1 Weight force on block 1 by Earth W1E = 0 i + -20 j N Normal force on block 1 by block 2: (two-subscript notation) Value = ——i + ——-j N FORCES on BLOCK 2 Weight force on block 2 by Earth W2E = 0 i + -20 j N Normal force on block 2 by block 1: (two-subscript notation) Value = ——i + ——j N Normal force on block 2 by Surface: (two-subscript notation) Value = ——i +——- j NCo A 4.0-kg block is stacked on top of a 12.0-kg block, which is accelerating along a horizontal table at a = 5.2 m/s' (Figure 1). Let µlk = Hs = l. Part A What minimum coefficient of friction u between the two blocks will prevent the 4.0-kg block from sliding off? Express your answer using two significant figures. Submit Request Answer Part B If u is only half this minimum value, what is the acceleration of the 4.0-kg block with respect to the table? Express your answer using two significant figures. ΑΣφ Figure m/s? 1 of 1 a = Submit Request Answer 4.0 kgThe cart in the figure is attached to special spring that can stretch and compress equally well. The springis very light. The cart and spring rest on a low-friction horizontal surface. The cart is pulled to position Iand then released. It moves to position V where it then reverses direction again to position I. A)Draw a force diagram forpoint I, cart moving left. B) Draw a force diagram forpoint III, cart moving left.