9:55 @← Expert Q&AYTE 929. A shunt motor runs at 1200 rpm on a 420 V circuit and current taken in 30 A inaddition to the field current. What resistance must be placed in series witharmature in order that the speed may be reduced to 600 rpm, the current throughthe armature remaining same. Ra = 302 given. (5.52)10.A 220 V DC series motor is running at a speed of 800 rpm and draws 100 A.Calculate at what speed the motor will run when developing half the torque.Armature + field resistance is 0.1 2. Assume that magnetic circuit is unsaturated.(1147 rpm.)11.230 V, DC shunt motor runs at 800 rpm and takes armature current of 50 A. Findthe resistance to be added to the field circuit to increase the speed from 800 rpmto 1000 rpm at an armature current of 80 A. Assume the flux to be proportionalto the field current. Given ra = 0.1502 and rf = 2500.(699.)■

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9. A shunt motor runs at 1200 rpm on a 420 V circuit and current taken in 30 A in addition to the field current. What resistance must be placed in series with armature in order that the speed may be reduced to 600 rpm, the current through the armature remaining same. Ra = 302 given. (5.52)

9. A shunt motor runs at 1200 rpm on a 420 V circuit and current taken in 30 A in addition to the field current. What resistance must be placed in series with armature in order that the speed may be reduced to 600 rpm, the current through the armature remaining same. Ra = 302 given. (5.52)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Three Phase Induction Motor

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Question

9:55 @
← Expert Q&A
YTE 92
9. A shunt motor runs at 1200 rpm on a 420 V circuit and current taken in 30 A in
addition to the field current. What resistance must be placed in series with
armature in order that the speed may be reduced to 600 rpm, the current through
the armature remaining same. Ra = 302 given. (5.52)
10.A 220 V DC series motor is running at a speed of 800 rpm and draws 100 A.
Calculate at what speed the motor will run when developing half the torque.
Armature + field resistance is 0.1 2. Assume that magnetic circuit is unsaturated.
(1147 rpm.)
11.230 V, DC shunt motor runs at 800 rpm and takes armature current of 50 A. Find
the resistance to be added to the field circuit to increase the speed from 800 rpm
to 1000 rpm at an armature current of 80 A. Assume the flux to be proportional
to the field current. Given ra = 0.1502 and rf = 2500.(699.)
■

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