9. An R-L series circuit contains a resistor and an inductor. The resistor has a value of 6.5 2. The circuit is connected to 120 V and has a current flow of 12 A. What is the inductive reactance of this circuit? 18.01 degrees 10. What is the voltage drop across the resistor in the circuit in Question 9? 11. A phase angle meter connected in an R-L series circuit indicates that the current is 28 degrees out of phase with the voltage. What is the circuit power factor?
9. An R-L series circuit contains a resistor and an inductor. The resistor has a value of 6.5 2. The circuit is connected to 120 V and has a current flow of 12 A. What is the inductive reactance of this circuit? 18.01 degrees 10. What is the voltage drop across the resistor in the circuit in Question 9? 11. A phase angle meter connected in an R-L series circuit indicates that the current is 28 degrees out of phase with the voltage. What is the circuit power factor?
Electrical Transformers and Rotating Machines
4th Edition
ISBN:9781305494817
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter3: Inductance In Alternating-current Circuits
Section: Chapter Questions
Problem 1RQ: How many degrees are the current and voltage out of phase with each other in a pure resistive...
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10 and 11
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Step 1
Question - 10:
The voltage drop across the resistor in an R-L series circuit can be found using Ohm's law, which states that the voltage across a resistor is equal to the current through the resistor multiplied by its resistance:
V = IR
Substituting the values, we get:
V = IR = 12 A * 6.5 ohms = 78 V
So the voltage drop across the resistor in the circuit is 78 V.
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