A 200-Kip 1oad P is applied to the pin-ended rectongular lumber column Shown below. The column is braced in the weak direction Shown below. The lumber used has an allowable stress in compraSSIon Gau=1500 psi and E= 450x 10? psi find the smablest cross secton that cam be uscd ; d-ab factor of safety of 2.5 P. 7 ft 8 ft B.
Q: The nails are on both sides of the beam and each can resist a shear of F. If the beam is subjected…
A: as we can know that maximum shear will occur at AB of a vlaues V(max)=(P+4.5)KN
Q: A uniformly distributed load, W1, is applied all throughout the length of the beam and a…
A: To Determine Depth of the beam , h
Q: Calculate the maximum allowable load (in kN) that a nominal 350mm x 350 mm sawn lumber column, 3.5m…
A: Solution-The given values are as follows,The column dimension=350×350The column…
Q: timber 1) The composite section shown, is subjected to a sagging bending moment of 100 kv.m,…
A:
Q: For the beam and loading shown design the cross section of the beam, knowing that the grade of…
A: We will find maximum bending moment and use bending equation
Q: Determinę the maximum allowable load P that can be safely supported by the frame if t = 32 mm and b…
A:
Q: Problem 8: A-C fc=4500 psi 2 in Grade 60 #6 bars - # 4 stirrups 1.5 in. clear cover 3/4 in. max.…
A: Given data: f'c=4500psi=31Mpafy=Grade 60=415Mpaeffective depth=d=20in=508mmMaximum depth ofneutral…
Q: When solving the problems for Section 1.6, assume that the material behaves linearly elastically.…
A: Given data in question Diameter Elasticity modulus Poissons ratio To find out Largest force P
Q: The wood pole is supported by two cables of 4- in diameter. The turn buckles in the cables are…
A: Draw the free body diagram.
Q: SAMPLE PROBLEM NO. 1 AT-beam has the following properties: br 820 mm, bw 250 mm, d 470 mm, t 100 mm.…
A: Flange width(bf)=820 mm Web width(bw)=250 mm Effective width(d)=470 mm Thickness(t)=100 mm Concrete…
Q: The assembly is used to support a 10 kN point load at the tip as shown. The steel rod has a diameter…
A:
Q: A steel bar is attached to a wood support beam with four 22 mm diameter lag screws, as shown in the…
A: Given ; Dia of lag screws = 22 mm width of steel bar = 69 mm thickness = 8mm the yield strength =…
Q: A wooden beam is fabricated from one 2 × 16 and two 2 × 10 dimension lumber boards to form the…
A: The given data is: A1=16*6=32 in2 y1=10+(2/2)=11 in A2=10*4=40 in2 y2=1/0/2=5 in
Q: Fill in the blanks: Determine the required tension steel area of the T beam with given properties…
A:
Q: prestressed T beam shown which is reinforced with à dl. n, fc' = 34.5 MPa, fpu = 1862 MPa, and the…
A:
Q: 1. A single span beam having an unsupported span of 20m carries a uniform load of "W" kN/m…
A:
Q: A cantilever timber beam with a span of L- 3.7 m supports a uniformly distributed load w. The beam…
A: Given data in question Cross section Bending stress Length To find out UDL value
Q: A cantilever timber beam with a span of L = 2.3 m supports a uniformly distributed load w. The beam…
A: Determine the magnitude of maximum load,W=?
Q: 5. The 600 mm x 600 mm tied column reinforced with 16 - 32 mmø symmetrically positioned where 5 bars…
A: Solution: Given: square column = 600 x600 mm fc = 28 MPa fy = 415MPa Ast = 16×π4×322=12867.96 mm2
Q: Calculate yield moment for the beam. Assume concrete accepts no tension. Use fc' = 4000 psi and =…
A:
Q: (a) Determine the provided (proy ), minimum (Pmin ), balanced (P), and maximum (Pmax ) steel ratios…
A:
Q: steel bar is attached to a wood support beam with four 20 mm diameter lag screws, as shown in the…
A: Given : Dia of lag screws = 20 mm width of steel bar = 60 mm and thickness = 5 mm yield strength =…
Q: A single rivet is used to join two plates as shown. If the diameter of the rivet is 3/4 inch and the…
A:
Q: A simply supported one way reinforced concrete floor slab has a span of 3 m. It carries a service…
A:
Q: A 4-m simply supported timber beam is to be designed to carry a total uniform load of 10 kN/m…
A:
Q: O A cube of wood (sG.0.6) hos gin. a side s. Compute the magnitude and direction of the force…
A: As per guidelines we can solve only one question at a time, please upload separately for…
Q: Design a corbel to support a factored vertical load of 120 kips acting at 5 in. from the face of a…
A: Solution: Given Data: Vu=120 kipsNu=20% of 120=24 kipsa= 5 inchfy=60000 psifc'=5000 psiNominal shear…
Q: 3. A reinforced rectangular concrete beam having a width of 300 mm, effective depth of 500 mm, fc’ =…
A: As per bartleby guidelines , experts are allowed to solve only first three parts. Please post other…
Q: A cantilever beam made of wood spans L = 5 ft. The beam has a rectangular cross section with a width…
A: Given data in question Length of beam Moment of inertia Cantilever beam Allowable shear stress…
Q: As shown in the figure below, a beam has a 9 - #42 reinforcement at tension and 6 - #25…
A: Solution: Given: f’c = 35 MPa, n = 8.2, fy = 400 MPa. = 58000 psi
Q: A composite beam is constructed using a steelplate (13 mm × 150 mm) with two wood beams (75 mm ×150…
A: Given data: Mz=6.75 kN.m
Q: for rectangular reinforced Con crete sectim t h= 680MMg d=600mm, b= 330mm, As = 6$16mm fx=22 MP ,…
A: Solution Given data: Dimension of rectangular reinforced section: Height(h)=680 mm effective…
Q: The column supporting the glued laminated peams in the previous example is to be left exposed. A…
A:
Q: Assume fy=345MPa and f'c=21 MPa. a. From the provided steel reinforcement, will the steel yield? b.…
A: Triangular beam Width 375mm Depth 375mm fc=21mpa fy=345mpa
Q: nated wood beam giuing (actual dimensions) cross section, as shown int 12 in. 3 in. 2 in. 2 in. 2…
A:
Q: The square wood beam ABEF is reinforced at the bottom by a steel plate with a rectangular…
A:
Q: PROBLEM NO. 4. A uniformly distributed load, W1, is appli all throughout the length of the beam anda…
A: First Calculate Bending moment at the section By calculating Reaction and take moment about left end…
Q: A cantilever timber beam with a span of L= 2.8 m supports a uniformly distributed load w. The beam…
A:
Q: L L T The wooden bar consists of two segments, each of length L. One segment has a square cross…
A:
Q: The joist AB used in housing construction is to be made rom 8-in. by 1.5-in. Southern-pine boards.…
A: The given data is: Dimensions of joist AB=8 in*1.5 in Allowable bending stress=1.5 psi Shear…
Q: a laminated beam is composed of four (4) planks, each of 150 mm x 30 mm, glued together to form a…
A:
Q: The nails are on both sides of the beam and cach can resist a shear of 3 KN. In addition to the…
A:
Q: A timber beam 4 m long is simply supported at both ends. It carries a uniform load of 15 kN/m…
A: GIVEN DATA, E= 7.31 GPA WIDTH OF BEAM = 220mm DEPTH OF BEAM = 250mm ACTUAL WIDTH OF BEAM =…
Q: a) Design the cantilever beam shown below. Assume p-0.005, bw-25cm and d=3cm. Use C20 concrete and…
A: Given:- ρ=0.005bw=25 cm=250 mmd'=3 cm=30 mmfc'=20 N/mm2fy=420 N/mm2
Q: The two pieces of wood, 2.62in. by 4.37 in., are glued together along the 510joint. Determine the…
A:
Q: ompute øM, för Use f. = compression steel yield in th lon Strength? eam si 4500 psi and fy = E %3D…
A:
Q: A rectangular fixed supported beam has the following properties. Compression steel if required shall…
A: This question belongs to subject Design of rcc structure. In this question find out area of tensile…
Q: Question 29 The laminated beam, shown in cross section, is composed of ?ve 6- in. by 2-in. planks…
A:
Q: If column AB is made from high strength pre-castconcrete and reinforced with four 20 mm diameter…
A: Given
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
- The rigid plate ABC shown in figure 2, was positioned on top of two identical steel posts, and the aluminum post was 0.1mm shorter than the steel posts at temperature of 50°C, if the allowable compressive stress in steel is limited to 120 MPa and in aluminum to 150 MPa, what is the maximum possible load P that can be supported on the rigid plate at temperature of 10°C ?Sawed lumber or surfaced lumber is planed of cleaned on at least one edge, for four side it is designated as a. S1S b. S2S c. S4S d. None of the aboveA W1422 acts compositely with a 4-inch-thick floor slab whose effective width b is 90 inches. The beams are spaced at 7 feet 6 inches, and the span length is 30 feet. The superimposed loads are as follows: construction load = 20 psf, partition load = 10 psf, weight of ceiling and light fixtures = 5 psf, and live load = 60 psf, A992 steel is used, and fc=4 ksi. Determine whether the flexural strength is adequate. a. Use LRFD. b. Use ASD.
- Note For Problems 9.6-1 through 9.6-5, use the lower-bound moment of inertia for deflection of the composite section. Compute this as illustrated in Example 9.7. 9.6-5 For the beam of Problem 9.4-2. a. Compute the deflections that occur before and after the concrete has cured. b. It the live toad deflection exceeds L360 , select another steel shape using either LRFD or ASD.A beam must be designed to the following specifications: Span length = 35 ft Beam spacing = 10 ft 2-in. deck with 3 in. of lightweight concrete fill (wc=115 pcf) for a total depth of t=5 in. Total weight of deck and slab = 51 psf Construction load = 20 psf Partition load = 20 psf Miscellaneous dead load = 10 psf Live load = 80 psf Fy=50 ksi, fc=4 ksi Assume continuous lateral support and use LRFD. a. Design a noncomposite beam. Compute the total deflection (there is no limit to be checked). b. Design a composite beam and specify the size and number of stud anchors required. Assume one stud at each beam location. Compute the maximum total deflection as follows: 1. Use the transformed section. 2. Use the lower-bound moment of inertia.Use an elastic analysis and determine the maximum load per inch of weld.
- Three steel bolts are to be used to attach thesteel plate shown to a wooden beam. Theplate will support a 110kN and the ultimateshearing stress for the steel used is 360MPaand that a factor of safety of 3.35 is desired,determine the increase in the bolt diameterrequired if an additional 100kN load is addedto the existing 110kN.(1) 21" 3" 4#9 bood 14" (1) Ec = ? (2) fr=? (3) Mer=? (5) #4 (4) When M = 70 & Mn = ? fé = 5 ksi Grade 60 Steel NWC. ft-k I 1R-2 Dr b=14", h=24" #4 tied stirrups. 4 #9 Rebars. fe=? Please write down units properly in the final answers. fs=?tf Sec Ag tw W16x100 29.4 0.585 0.985 Bolt (7/8 in) A structural analysis was done for -1 the steel section whose shape and characteristics are shown below, and the outputs were arranged in the table below. Choose the appropriate amount, knowing that .all numbers are in units (ksi, in) O fy ( 36 fu 0.85 20.149 584.3 635.04 58 D(bolt) 7/8 P Maximum tensile force (P) that can be exerted Effective cross- sectional area (Ae) The value of T1 Modulus M (mo) !
- 4. The tension member shown below is a C 310 x 30.8 of A572M gr 345 steel materials. Will it safely support a service dead load of 265 kN and a service live load of 555 kN. L 50 102.5 102.5 50 65 65 65 O O 22 veny diameter bolts C310 x 30.8 Iso A36M stool matorial and select a double anglo tonsion member to rosistPabacboadcom Question Campletion Stutn MOD LE 4 A Movtng to another question will save this response Question 1 A hwo span beam subjected to shear and flexure only is reinforced as follows: @ MIDSPAN 2-016 mm 3-016 mm SECTION @ FACE OF SUPPORTS TOP BARS BOTTOM BARS 5-016 mm 2-016 mm Given: Stirrup diameter, dg - 10 mm Concrete fe=21 MPa Steel rebar fy 415 MPa Stirrup fy= 275 MPa Beam sizebxh=250 mm x 450 mm Assume all bars laid out in single layer. Calculate the following: Tensile steel ratio in positive bending at midspan = (in 5 decimal places) Design Moment strength of section at midspan for positive bending = kN-m (nearest whole number) kN m (nearest whole number) Nominal Moment strength of section at face of support for negative bending =Compute the maximum acceptable tensile SERVICE LOAD that may act on a single tee section that is connected to a gusset plate using welds 12 inches long, as shown in the figure. The service live load is three times the dead load. Use A992 steel. USE LRFD ONLY, no block shear will occur. What is the Governing Ultimate Tensile Capacity based on Net Fracture Round your answer to 3 decimal places.