A 3.026 grams of Cu (II) salt is dissolved in water and then diluted to 250 mL in a volumetric flask. Iodine is liberated when one gram of KI solution is added to 50.0 mL of aliquot sample. A 23.33 mL of 0.04668 M Na,S,O, solution is required to titrate the iodine liberated. Calculate the weight percent of the Cu in the salt. (A) 11.43%, just before end point (B) 12.43%, just before end point (C) 11.43%, after equivalence point (D) 12.43%, after equivalence point

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
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Chapter4: Reactions In Aqueous Solution
Section: Chapter Questions
Problem 78QAP: When 85.0 mL of 0.250 M Ba(OH)2 solution is added to 85.00 mL of 0.250 M Al (NO3)3 solution, a white...
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A 3.026 grams of Cu (II) salt is dissolved in water and then diluted to 250 mL in a volumetric
flask. Iodine is liberated when one gram of KI solution is added to 50.0 mL of aliquot sample. A
23.33 mL of 0.04668 M Na,S,O, solution is required to titrate the iodine liberated. Calculate the
weight percent of the Cu in the salt.
(A) 11.43%, just before end point
(B) 12.43%, just before end point
(C) 11.43%, after equivalence point
(D) 12.43%, after equivalence point
Transcribed Image Text:A 3.026 grams of Cu (II) salt is dissolved in water and then diluted to 250 mL in a volumetric flask. Iodine is liberated when one gram of KI solution is added to 50.0 mL of aliquot sample. A 23.33 mL of 0.04668 M Na,S,O, solution is required to titrate the iodine liberated. Calculate the weight percent of the Cu in the salt. (A) 11.43%, just before end point (B) 12.43%, just before end point (C) 11.43%, after equivalence point (D) 12.43%, after equivalence point
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