A 3.50-g sample of aluminum pellets (specific heat capacity - 0.89 JC-g) and a 21.50-g sample of iron pellets (specific heat capacity = 0.45 JCg) are heated to 100.0 "C. The mixture of hot iron and aluminum is then dropped into 65.5 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings. Final temperature °C

Chemistry: An Atoms First Approach
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Chapter7: Chemical Energy
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Problem 55E: A 5.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/C g) and a 10.00-g sample of...
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A 3.50-g sample of aluminum pellets (specific heat capacity 0.89 JC-g) and a 21.50-g sample of iron pellets (specific heat capacity = 0.45 JCg) are heated to 100.0 "C. The
mixture of hot iron and aluminum is then dropped into 65.5 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the
surroundings.
Final temperature
°C
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Transcribed Image Text:A 3.50-g sample of aluminum pellets (specific heat capacity 0.89 JC-g) and a 21.50-g sample of iron pellets (specific heat capacity = 0.45 JCg) are heated to 100.0 "C. The mixture of hot iron and aluminum is then dropped into 65.5 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings. Final temperature °C Submit Answer Try Another Version 6 item attempts remaining
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