A 500-ft curve, 9₁ = -2.00%, g₂ = +3.00%, VPI station = 98 + 10, VPI elevation = 5388.26 ft, stakeout at full stations. Part A List station elevations for an equal-tangent parabolic curve for the data given. Give the elevations in order of increasing X. Express your answers in feet to six significant figures separated by commas. -- ΑΣΦ ↓↑ Submit vec Elev = 831.010,833.010,834.010,834.010,833.010,831.010,831.010 ft Previous Answers Request Answer

A 500-ft curve, 9₁ = -2.00%, g₂ = +3.00%, VPI station = 98 + 10, VPI elevation = 5388.26 ft, stakeout at full stations. Part A List station elevations for an equal-tangent parabolic curve for the data given. Give the elevations in order of increasing X. Express your answers in feet to six significant figures separated by commas. -- ΑΣΦ ↓↑ Submit vec Elev = 831.010,833.010,834.010,834.010,833.010,831.010,831.010 ft Previous Answers Request Answer

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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1. Draw a simple horizontal curve label the curve and define each term 2. For the curve data shown calculate deflection angles also tabulate and show all necessary calculationsalso briefly explain layout method based on your resultsI= 42° 16’ 00” D= 4° 0’ 0”, PI station =93+62.71 3- Highway curve with R = 1000ft ,I = 60° 00’ 00”and PI =85+40Complete the curve calculations showing all details
topic: fundamentals of surveying A vertical sag parabolic curve CD, 620 meters long is connected by tangents having a downgrade 0f 6.2% and upgrade of 4.2% intersecting at station 18+254.4 and elevation 54.25m. Find the distance from D to the lowest point of the curve.
Please Handwrite Answer! Horizontal highway curve: Given PI at 95 + 54.78, Δ = 24°28’, and D = 5°30’, compute thedeflections to the nearest second for the full stations (means stations 94+00, 95+00, 96+00, etc.)as well as for the beginning and end of the curve.
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Given: R=310m PI chainage = 905.280m BC station = 639.280m EC chainage = 1138.491m Determine : a. tangent length b. curve central angle c. length of curve
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Horizontal highway curve: Given PI at 95 + 54.78, Δ = 24°28’, and D = 5°30’, compute thedeflections to the nearest second for the full stations (means stations 94+00, 95+00, 96+00, etc.)as well as for the beginning and end of the curve.
A circular road is proposed to be laid out with tangent AB whose bearing is N85º54’E intersecting another tangent line BC whose bearing is N48º30’E. If the degree of the curve is 4.5º, using arc basis, determine the following: External distance, E Length of the road, LC If the station of point B 10+584, determine the station of PT.
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