A +6.50 µC point charge is moving at a constant 8.00 × 106 m/s in the +y-direction, relative to a reference frame. At the instant when the point charge is at the origin of this reference frame, find the magnetic- field vector B it produces at point x = 0, y = -0.500 m, z = +0.500 m. Enter your answers numerically separated by commas. |B2, By, B₂ = Submit 15| ΑΣΦ a b xa Xb √x vx Previous Answers Request Answer x X Incorrect; Try Again; 6 attempts remaining | Review | Constants <४ ? |X| X.10n X T

A +6.50 µC point charge is moving at a constant 8.00 × 106 m/s in the +y-direction, relative to a reference frame. At the instant when the point charge is at the origin of this reference frame, find the magnetic- field vector B it produces at point x = 0, y = -0.500 m, z = +0.500 m. Enter your answers numerically separated by commas. |B2, By, B₂ = Submit 15| ΑΣΦ a b xa Xb √x vx Previous Answers Request Answer x X Incorrect; Try Again; 6 attempts remaining | Review | Constants <४ ? |X| X.10n X T

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Consider (Figure 1). Figure y (cm) 1 ^ 2.0 × 10² m/s Proton -x (cm) 1 of 1 Part A What is the magnetic field at the position of the dot in (Figure 1)? Give your answer as the components of a vector. Consider a right-handed coordinate system. Enter the components of the magnetic field in femtoteslas separated by commas. ► View Available Hint(s) Bx, By, B₂ = Submit Provide Feedback VE ΑΣΦ P Pearson ? fT Copyright © 2023 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us | Next >
A+5.00 µC point charge is moving at a constant 9.00 x 10° m/s in the +y-direction, relative to a reference frame. Part A At the instant when the point charge is at the origin of this reference frame, find the magnetic-field vector B it produces at point z = 0.500 m, y = 0, z= 0. Enter your answers numerically separated by commas. ΑΣφ Bz, By, Bz = Submit Request Answer Part B At the instant when the point charge is at the origin of this reference frame, find the magnetic-field vector B it produces at point r = 0, y = -0.500 m, z = 0. Enter your answers numerically separated by commas. Bz, By, B2 =
Solve the following: A proton (of mass, m-1.67 x 1027kg) starts moving in a circular path of radius 5 cm when it enters perpendicular to the Earth's magnetic field of 1.75 x 10-5 T. Calculate Bin the speed X. of the cosmic ray proton in (m/s) ? X +q tu
This problem is in 3D. P is the center. Out of the page is a distance z from P. Let this z be 0.02 m. Calculate the "net" magnetic field at z provided that 1 = 395 A, a = 0.03 m, and b = 0.05 m. Use Ho = 1.257x10-6 Wb/Am b NOTE: You will use here the right hand rule and superposition of magnetic field. Out of the page is +, while into the page is -. Final answer in FIVE decimal places. Ignore the effects of the straight wire at the bottom. Include the SI unit.
A +5.00 uC point charge is moving at a constant 9.00 x 10° m/s in the +y-direction, relative to a reference frame. Part C At the instant when the point charge is at the origin of this reference frame, find the magnetic-field vector B it produces at point z = 0, y = 0, z= +0.500 m. Enter your answers numerically separated by commas. B, By, Bz = 18,0,0 Submit Previous Answers Request Answer X Incorrect; Try Again; 9 attempts remaining Part D At the instant when the point charge is at the origin of this reference frame, find the magnetic-field vector B it produces at point r = 0, y = -0.500 m, z= +0.500 m Enter your answers numerically separated by commas. ΑΣφ Bz, By. В, В. -
The figure shows crossed uniform electric and magnetic fields and, at a certain instant, the velocity vectors of the 10 charged particles listed in the table. (The vectors are not drawn to scale.) The speeds given in the table are either less than or greater than E/B (see out of the page toward you after the instant shown in the figure? (Several choices may be Question 1). Which particles will move correct.) HUFI Particle Charge Speed 1 2 3 4 5 + + Less Greater Less Greater Less Particle Charge 6 7 10 10 + + Speed Greater Less Greater Less Greater 4
Electric field vector E and magnetic field vector B have dot product of -6.00 and their cross product has a magnitude of +9.00. What is the angle between these two vector? Please show the complete solution and figure. Solution must be readable. Thank youZ
A metal cube with sides of length a is moving at velocity v=voj across a uniform magnetic field B = Bok. The cube is oriented so that four of its edges are parallel to its direction of motion (i.e., the normal vector of two faces are parallel to the direction of motion). (Figure 1) Figure Bo N 1 of 1 Vo Part A Find E, the electric field inside the cube. Express the electric field in terms of vo, Bo, and unit vectors (i, j, and/or k). E = Submit Part B V ΑΣΦ -î Request Answer Now, instead of electrons, suppose that the free charges have positive charge q. Examples include "holes" in semiconductors and positive ions in liquids, each of which act as "conductors" for their free charges. www. J? If one replaces the conducting cube with one that has positive charge carriers, in what direction does the induced electric field point? Submit Request Answer
Part A through Part D Please and thank you. A +6.50-μC point charge is moving at a constant 9.00×10^6m/sin the +y-direction, relative to a reference frame. At the instant when the point charge is at the origin of this reference frame, find the magnetic-field vector B⃗ it produces at the following points. Find Bx, By, Bz for each part. Part A x=0.500m, y=0, z=0. Part B x=0, y=−0.500m, z=0 Part C x=0, y=0, z=+0.500m Part D x=0, y=−0.500m, z=+0.500m
The force experienced by a test charge q at a point in a region of electric and magnetic fields are given as follows: F1 = 0 for v = Voax F2 = 0 for v = Voay F3 = -[f3]qEoaz for v = vola, + 2a,) Where vọ and Eo are constants. What is the expression for B at that point. O Egaz O (Eo / volaz O Edlax - a,) O (Eo / vol(ax - a,)
Figure 1 shows a square coil of side 4.5 cm. A battery is connected to the coil and produces a current of 6.8 A. The coil is placed in a uniform magnetic field of flux density 5.67 mT as shown in Figure 1. A D 0o Figure 1 Calculate the size and direction of the electromagnetic force that will act on side AB. Calculate the size and direction of the electromagnetic force that will act on side BC. Describe the motion of the frame immediately after the current in the frame is switched on. The battery is removed from the coil and the coil is mechanically rotated 90° clockwise. State the direction of the induced current on side AB. North Pole South Pole
Electric field vector E and magnetic field vector B have dot product of -6.00 and their cross product has a magnitude of +9.00. Ehat is the angle between these two vector?