a- Assume that the active component of the load on the circuit is 0.6 p.u. Find the initial power angle 8. b- With the value of the load set at 0.6 p.u., a three-phase short circuit takes place in the middle of transmission line 1. Will the system be stable under a sustained fault? c- Assume that the active component of the load on the circuit is 0.3 p.u. Find the initial power angle 6. d- With the value of the load set at 0.3 p.u., a three-phase short circuit takes place in the middle of transmission line 1. Will the system be stable under a sustained fault?

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Problem 7
Consider the circuit shown in Fig. (5) Assume that E = 1.25 p.u., and V= 1.00 p.u.
a- Assume that the active component of the load on the circuit is 0.6 p.u. Find the initial power angle 8.
b- With the value of the load set at 0.6 p.u., a three-phase short circuit takes place in the middle of transmission line
1. Will the system be stable under a sustained fault?
c- Assume that the active component of the load on the circuit is 0.3 p.u. Find the initial power angle 8.
d- With the value of the load set at 0.3 p.u., a three-phase short circuit takes place in the middle of transmission line
1. Will the system be stable under a sustained fault?
Line 1 X =0.75
X = 0.3
Tr
G
Vous = 1.0
Line 2 X =0.75
X = 0.5
Line 3 X =0.75
Figure (5) Circuit for Problem (7)
Transcribed Image Text:Problem 7 Consider the circuit shown in Fig. (5) Assume that E = 1.25 p.u., and V= 1.00 p.u. a- Assume that the active component of the load on the circuit is 0.6 p.u. Find the initial power angle 8. b- With the value of the load set at 0.6 p.u., a three-phase short circuit takes place in the middle of transmission line 1. Will the system be stable under a sustained fault? c- Assume that the active component of the load on the circuit is 0.3 p.u. Find the initial power angle 8. d- With the value of the load set at 0.3 p.u., a three-phase short circuit takes place in the middle of transmission line 1. Will the system be stable under a sustained fault? Line 1 X =0.75 X = 0.3 Tr G Vous = 1.0 Line 2 X =0.75 X = 0.5 Line 3 X =0.75 Figure (5) Circuit for Problem (7)
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