A band-pass filter can be constructed by cascading two Sallen-Key filters of the active high-pass filter and low-pass. The two filters produce a band-pass filter where the low corner frequency, f = 300 kHz whereas the high-corner frequency, fH= 500 kHz. 1. Calculate the resistances (RA1, RA2, R81, Rg2) for both filters by using these capacitors value, CA1= Ca2 = C81 = C82 = 7pF. In addition, the value of the resistors must follow these conditions: the resistance in low-pass filter is RA2=2RA1 and in high-pass filter is Rg1=3R82.

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A band-pass filter can be constructed by cascading two Sallen-Key filters of the active high-pass filter and low-pass. The
two filters produce a band-pass filter where the low corner frequency, f = 300 kHz whereas the high-corner frequency,
fH = 500 kHz.
1. Calculate the resistances (RA1, RA2, R31, R32) for both filters by using these capacitors value, CA1= CA2 = C31 = C32 = 7pF.
In addition, the value of the resistors must follow these conditions: the resistance in low-pass filter is RA2=2RA1 and in
high-pass filter is R81=3R82.
Answer : RA1 =
RA2 =
R81 =
ko
R82 =
ko
2. Calculate center frequency and bandwidth.
Answer : Center frequency , fo=
kHz
Bandwidth, BW=
kHz
Transcribed Image Text:A band-pass filter can be constructed by cascading two Sallen-Key filters of the active high-pass filter and low-pass. The two filters produce a band-pass filter where the low corner frequency, f = 300 kHz whereas the high-corner frequency, fH = 500 kHz. 1. Calculate the resistances (RA1, RA2, R31, R32) for both filters by using these capacitors value, CA1= CA2 = C31 = C32 = 7pF. In addition, the value of the resistors must follow these conditions: the resistance in low-pass filter is RA2=2RA1 and in high-pass filter is R81=3R82. Answer : RA1 = RA2 = R81 = ko R82 = ko 2. Calculate center frequency and bandwidth. Answer : Center frequency , fo= kHz Bandwidth, BW= kHz
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