A beam supports both a uniform distributed load and a concentrated force, as shown in the figure below. The uniform distributed load has a magnitude q = 700 lb/ft and extends across the entire beam. The concentrated force has a magnitude F = 22 kip and acts L = 9 ft to the right of point A. The beam has an overall length L = 24 ft, and is held in equilibrium by a pin at point A and a roller at point B. Neglect the height and weight of the beam for this analysis. Determine the internal shear force (V) and internal bending moment (M) at the following locations: F A ΑΙ V₁ = M₁ = LE F number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) (b) A point x₂ = 22 ft to the right of point A. V₂ = M2 = Note: Express your answers following the standard positive sign convention described in the Internal Loads - Positive Sign Convention document. (a) A point x₁ = 4 ft to the right of point A. L number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) kip kip - ft kip q kip - ft B 77

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter10: Statically Indeterminate Beams
Section: Chapter Questions
Problem 10.4.39P: A beam supporting a uniform load of intensity q throughout its length rests on pistons at points A,...
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A beam supports both a uniform distributed load and a concentrated force, as shown in the figure below. The
uniform distributed load has a magnitude q = 700 lb/ft and extends across the entire beam. The
concentrated force has a magnitude F = 22 kip and acts L = 9 ft to the right of point A. The beam has an
overall length L = 24 ft, and is held in equilibrium by a pin at point A and a roller at point B. Neglect the
height and weight of the beam for this analysis. Determine the internal shear force (V) and internal bending
moment (M) at the following locations:
F
A ΑΙ
V₁ =
M₁ =
LE
F
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
(b) A point x₂ = 22 ft to the right of point A.
V₂ =
M2
=
Note: Express your answers following the standard positive sign convention described in the Internal Loads -
Positive Sign Convention document.
(a) A point x₁ = 4 ft to the right of point A.
L
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
kip
kip - ft
kip
q
kip - ft
B
77
Transcribed Image Text:A beam supports both a uniform distributed load and a concentrated force, as shown in the figure below. The uniform distributed load has a magnitude q = 700 lb/ft and extends across the entire beam. The concentrated force has a magnitude F = 22 kip and acts L = 9 ft to the right of point A. The beam has an overall length L = 24 ft, and is held in equilibrium by a pin at point A and a roller at point B. Neglect the height and weight of the beam for this analysis. Determine the internal shear force (V) and internal bending moment (M) at the following locations: F A ΑΙ V₁ = M₁ = LE F number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) (b) A point x₂ = 22 ft to the right of point A. V₂ = M2 = Note: Express your answers following the standard positive sign convention described in the Internal Loads - Positive Sign Convention document. (a) A point x₁ = 4 ft to the right of point A. L number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) kip kip - ft kip q kip - ft B 77
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