A block of mass m = 3.59kg moves along the x-axis subject to a net force which depends on position. The force is Fer(x) = (-3.92x-1.49x³). The block is initially at x = 0m moving with velocity = -3.731. (The input below will accept answers with no more than 1% variation from the correct value.) What is the smallest value of x the block reaches? Hint: Calculate the work done as a function of x, and then solve the resulting quadratic expression for x². What is the block's speed when it reaches x = 1.62m? m El

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A block of mass m = 3.59kg moves along the x-axis subject to a net force which depends on position.
The force is Fner (x) = (-3.92x-1.49x³) î.
The block is initially at x = Om moving with velocity = -3.73.
(The input below will accept answers with no more than 1% variation from the correct value.)
What is the smallest value of x the block reaches?
m
Hint: Calculate the work done as a function of x, and then solve the resulting quadratic expression for x².
What is the block's speed when it reaches x = 1.62m?
Ev
Transcribed Image Text:A block of mass m = 3.59kg moves along the x-axis subject to a net force which depends on position. The force is Fner (x) = (-3.92x-1.49x³) î. The block is initially at x = Om moving with velocity = -3.73. (The input below will accept answers with no more than 1% variation from the correct value.) What is the smallest value of x the block reaches? m Hint: Calculate the work done as a function of x, and then solve the resulting quadratic expression for x². What is the block's speed when it reaches x = 1.62m? Ev
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