A body at a temperature of 50 deg. F is placed outdoors where the temperature is 100 deg. F. If after 5 minutes the temperature of the body is 60 deg. F, find the temperature of the body after 25 minutes. Select the correct response: 83.77 deg. F None 79.5 deg. F 87.04 deg. F
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- Use Newton's Law of cooling to determine the k value in air temperature of 40 degC. If 30 mins ago the boy was 120 degC and 10 mins age it was 80 degC. Select the correct response: 0.0321 -0.321 0.0235 -0.0235 none of the choicesTRUE OR FALSE: 1.A linear differential equation of the higher order is one which contains the dependent variable and all its derivatives to the first degree only. 2.The surface temperature of a cooling object changes at a rate proportional to the difference between the surface and ambient temperatures.A body at a temperature of 50 deg. Fis placed outdoors where the temperature is 100 deg. F. If after 5 minutes the temperature of the body is 60 deg. F, find the temperature of the body after 30 minutes. Select the correct response: 79.5 deg. F None O 83.77 deg. F 87.04 deg. F
- The left side of this equation tells how much energy Q the cylinder gives to the water while it cools. The right side of this equation tells how much energy Q the water and aluminum cup absorb from the cylinder to warm up. Because it is the same energy, they are equal. What is known in this equation? Mcyl 411.7 g, malum 46.5 g, malum+water = 175 g Can you find: mwater =? g Twater = Talum = 20°C (water and cup of room temperature) 90°C, T; = 35°C (hot cylinder and cool "cylinder+cup+water" temperatures) Tcyl kCal Calum = 0.22, Cwater 1 (specific heat of water and aluminum, measured in units kg-°C What are we looking for is Ccul - How we find it? Plug all the numbers into the equation (1), Ccul will be one unknown which you can calculate from the equation. Important, convert all the masses from grams to kilograms! After you find Ccyl, compare it to known value for the copper 0.093(our cylinder is made out of copper). |Ceyl -0.093| % : · 100% 0.093Q3: Consider evaluation of different temperatures of solar photovoltaic/thermal system (PVT) as shown in Figure 1(a). The following set of differential equations represent energy balance equations to be solve using matrices and eigenvalues using MATLAB: dTglass = -0.75Tgtass + 0.75TpvT (1) dt - 1.187glass – 22Tpyr + 23Twax (2) dt dTwax 12Tglass + 18TpyT – 19 Twax (3) dt Where, Tgtass , TPVT, and Twax, are temperatures illustrated in Figure 1(b). At time t-0 the initial conditions are Tglass = 35 , Tpyr = 33, and Twax = 31 °C. Cold suppty In frem water Tank Glass PVT Espann Nane-PCMPVT Collector Wax Tubes Sterg Tank Nanofluid Heat Exchanger Contalner Tepe Teek oe Pump for drain1. Determine the equivalent spring stiffness constant of the following. 150 N/m 240 N/m 60 N/m wwwwwww 290 N/m 105 N/m wwwwww 35 N/m a. 250 N/m www 145 N/m F Ans:
- A thermocouple is used to measure the temperature T1. The thermocouple reference junction labeled 2 is at a temperature of 20°C. The voltage output is measured using a potentiometer and found to be 4.686 mV. What is T1 in degrees RK: if the temperature values are not in the table, you have to use interpolation. Select one: O a. 98 O b. 118 O c. 105 O d. 108 Previous page Next pageQi: (50 marks) Find the total heat flux of the composite wall when: B KA = KC = KF = 15 m. K KB = KD = 10 m. K KE = KG = 20 %3D m. K D. Height of B = C = D 4 cm 3 cm 4 cm 6 cm Height of F = G AT = 30 KSolve the following problems. 1. A thermometer reading 18 F is brought into a room where the temperature is 70'F, 1min later the thermometer reading is 31°F. Determine the temperature reading as a function of time and in particular, find the temperature reading 5 min after the thermometer is first brought into the room.
- Q3: Consider evaluation of different temperatures of solar photovoltaic/thermal system (PVT) as shown in Figure 1(a). The following set of differential equations represent energy balance equations to be solve using matrices and eigenvalues dTglass = -0.75Tglass + 0.75TPVT (1) dt - 1.18Tglass – 22TpyT + 237wax (2) dt dTwax 12Tglass + 18TpyT – 19 Twax (3) dt Where, Tptass, TPVT, and Twax, are temperatures illustrated in Figure 1(b). At time t-0 the initial conditions are Tglass = 35 , Tpyr = 33, and Twax = 31 °C. Cold sappty In frem water Tank Glass PVT Enpann Nane-PCMPVT Collector Wax Tubes Sterg Tank Mat Nanofluid Heat Exchanger Tepe Contalner Tuek et Pump for drainDifferential Equation: Newton's Law of Cooling. Show your complete solution.A thermometer reading 10ᵒC is brought into a room where the temperature is 32ᵒC. Two minutes later the thermometer reading is 15ᵒC. Determine the temperature reading 5 minutes after the thermometer is first brought into the room.4- A thermometer having a time constant of 0.4 min. is placed in a temperature bath and after the thermometer comes to equilibrium with the bath, the temperature of the bath is increased linearly with time at the rate of 2 deg.C min. what is the difference between the indicated temperature and bath temperature after : (a) 2 min. (b) 20 min.