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A breast cancer tumour is classified as T2 if it is between 2-5 cm in diameter.  A group of 15 breast cancer patients were classified as having T2 tumours.  They tried an experimental drug for 3 months and then had their tumours remeasured.  Below are the results (in cm):  Before Treatment:                     Mean = 3.74    Standard deviation = 0.80     After 3 Months of Treatment:   Mean = 3.04    Standard deviation = 0.70    Sum of the differences = -10.5 Sum of the differences, squared = 110.25 Sum of squared differences = 8.57 What are the degrees of freedom?  Write a null and alternative hypothesis and determine, at α = 0.05,if the experimental drug decreased tumour size?

A breast cancer tumour is classified as T2 if it is between 2-5 cm in diameter.  A group of 15 breast cancer patients were classified as having T2 tumours.  They tried an experimental drug for 3 months and then had their tumours remeasured.  Below are the results (in cm):  Before Treatment:                     Mean = 3.74    Standard deviation = 0.80     After 3 Months of Treatment:   Mean = 3.04    Standard deviation = 0.70    Sum of the differences = -10.5 Sum of the differences, squared = 110.25 Sum of squared differences = 8.57 What are the degrees of freedom?  Write a null and alternative hypothesis and determine, at α = 0.05,if the experimental drug decreased tumour size?

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section: Chapter Questions
Problem 22SGR
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A breast cancer tumour is classified as T2 if it is between 2-5 cm in diameter.  A group of 15 breast cancer patients were classified as having T2 tumours.  They tried an experimental drug for 3 months and then had their tumours remeasured.  Below are the results (in cm): 

Before Treatment:                     Mean = 3.74    Standard deviation = 0.80    

After 3 Months of Treatment:   Mean = 3.04    Standard deviation = 0.70   

Sum of the differences = -10.5

Sum of the differences, squared = 110.25

Sum of squared differences = 8.57

What are the degrees of freedom?  Write a null and alternative hypothesis and determine, at α = 0.05,if the experimental drug decreased tumour size? 

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