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(a) By proper manipulation, put the wideband band-pass function of Eq. (3.29a) in the standard form H (jo) = HOBP HBP. (b) Show that no matter how you select @ and wH, the Q of that filter can never exceed. This is why the filter is called wideband.

(a) By proper manipulation, put the wideband band-pass function of Eq. (3.29a) in the standard form H (jo) = HOBP HBP. (b) Show that no matter how you select @ and wH, the Q of that filter can never exceed. This is why the filter is called wideband.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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3.4 Standard second-order responses 3.23 (a) By proper manipulation, put the wideband band-pass function of Eq. (3.29a) in the standard form H (jw) = HOBP HBP. (b) Show that no matter how you select w, and @H, the Q of that filter can never exceed. This is why the filter is called wideband.
Transcribed Image Text:3.4 Standard second-order responses 3.23 (a) By proper manipulation, put the wideband band-pass function of Eq. (3.29a) in the standard form H (jw) = HOBP HBP. (b) Show that no matter how you select w, and @H, the Q of that filter can never exceed. This is why the filter is called wideband.
this is a second-order filter, we have chosen to discuss it here to demonstrate the indicating a zero at the origin and two real poles at -1/R₁C₁ and -1/R2C2. Though use of lower-order building blocks to synthetize higher-order filters. Letting s→ jw First-Order Active 129 SECTION 3.2 yields 1346 (3.29a) H(jw) = Ho jw/wL (1 + jw/wL)(1 + jw/wH).
Transcribed Image Text:this is a second-order filter, we have chosen to discuss it here to demonstrate the indicating a zero at the origin and two real poles at -1/R₁C₁ and -1/R2C2. Though use of lower-order building blocks to synthetize higher-order filters. Letting s→ jw First-Order Active 129 SECTION 3.2 yields 1346 (3.29a) H(jw) = Ho jw/wL (1 + jw/wL)(1 + jw/wH).
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