A carnival game is designed so that approximately 10% of players will win a large prize. If there is evidence that the percentage differs significantly from this target, then adjustments will be made to the game. To investigate, a random sample of 100 players is selected from the large population of all players. Of these players, 19 win a large prize. The question of interest is whether the data provide convincing evidence that the true proportion of players who win this game differs from 0.10. The computer output gives the results of a z-test for one proportion. Test and CI for One Proportion Test of p = 0.1 vs p * 0.1 Sample X N Sample 1 19 100 Р 95% CI (0.113, 0.267) 0.19 What conclusion should be made at the a = 0.05 level? O Because the P-value < a= 0.05, there is convincing evidence that the true proportion of players who win this game differs from 0.10. Z-Value 3.00 P-value 0.0027

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
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Chapter11: Data Analysis And Probability
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Statistics - MA3113 B-IC-Edgenuity.com
95% CI Z-Value P-value
(0.113, 3.00
0.267)
0.0027
5/25/22, 12:44 PM
A carnival game is designed so that approximately
10% of players will win a large prize. If there is
evidence that the percentage differs significantly
from this target, then adjustments will be made to
the game. To investigate, a random sample of 100
players is selected from the large population of all
players. Of these players, 19 win a large prize. The
question of interest is whether the data provide
convincing evidence that the true proportion of
players who win this game differs from 0.10. The
computer output gives the results of a z-test for one
proportion.
Test and CI for One Proportion
Test of p= 0.1 vs p = 0.1
Sample X N
Sample
1
19 100
Р
0.19
What conclusion should be made at the a = 0.05
level?
O Because the P-value < a = 0.05, there is
convincing evidence that the true proportion of
players who win this game differs from 0.10.
O Because the P-value < a = 0.05, there is
convincing evidence that the true proportion of
players who win this game differs from 0.19.
O Because the P-value <a = 0.05, there is not
convincing evidence that the true proportion of
players who win this game differs from 0.10.
O Because the P-value <a = 0.05, there is not
convincing evidence that the true proportion of
players who win this game differs from 0.19.
https://i03.core.learn.edgenuity.com/player/
Transcribed Image Text:Statistics - MA3113 B-IC-Edgenuity.com 95% CI Z-Value P-value (0.113, 3.00 0.267) 0.0027 5/25/22, 12:44 PM A carnival game is designed so that approximately 10% of players will win a large prize. If there is evidence that the percentage differs significantly from this target, then adjustments will be made to the game. To investigate, a random sample of 100 players is selected from the large population of all players. Of these players, 19 win a large prize. The question of interest is whether the data provide convincing evidence that the true proportion of players who win this game differs from 0.10. The computer output gives the results of a z-test for one proportion. Test and CI for One Proportion Test of p= 0.1 vs p = 0.1 Sample X N Sample 1 19 100 Р 0.19 What conclusion should be made at the a = 0.05 level? O Because the P-value < a = 0.05, there is convincing evidence that the true proportion of players who win this game differs from 0.10. O Because the P-value < a = 0.05, there is convincing evidence that the true proportion of players who win this game differs from 0.19. O Because the P-value <a = 0.05, there is not convincing evidence that the true proportion of players who win this game differs from 0.10. O Because the P-value <a = 0.05, there is not convincing evidence that the true proportion of players who win this game differs from 0.19. https://i03.core.learn.edgenuity.com/player/
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