A certain cable, 504.76 ft long is suspended between two supports at the same elevation and 500 ft apart, the load is 500 lbs per horizontal foot including the weight of the cable. Calculate the sag of this cable using Newton-Raphson method up to 5 iterations with initial guess of d (sag) 10 ft. Use parabolic equation. Parabolic Equation: 8d? 32d4 s = L+ 3L 5L3 Where: S length of the cable L distance between two supports

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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A certain cable, 504.76 ft long is suspended between two supports at
the same elevation and 500 ft apart, the load is 500 lbs per horizontal
foot including the weight of the cable. Calculate the sag of this cable
iterations with initial guess of d
using Newton-Raphson method up to 5
10 ft. Use parabolic equation.
(sag)
Parabolic Equation:
8d?
32d*
s = L+
3L
5L3
Where:
length of the
cable
S
L
distance between two supports
Transcribed Image Text:A certain cable, 504.76 ft long is suspended between two supports at the same elevation and 500 ft apart, the load is 500 lbs per horizontal foot including the weight of the cable. Calculate the sag of this cable iterations with initial guess of d using Newton-Raphson method up to 5 10 ft. Use parabolic equation. (sag) Parabolic Equation: 8d? 32d* s = L+ 3L 5L3 Where: length of the cable S L distance between two supports
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