A certain processor uses a fully associative cache of size 16 kB. The cache block size is 16 bytes. Assume that the main memory is byte addressable and uses a 32-bit address. How many bits are required for the Tag and the Index tickds respectively in the addresses generated by the processor?
Q: Suppose a computer using direct-mapped cache has 232 bytes of byte-addressable main memory and a…
A:
Q: Suppose a computer using direct-mapped cache has 232 bytes of byte-addressable main memory and a…
A:
Q: Suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and a…
A: Size of tag and offset fields The memory with 224 bytes consists of 24 addressable bytes. Hence 24…
Q: Suppose a computer using direct-mapped cache has 232 bytes of byte-addressable main memory and a…
A: Given Information is as follow: Size of the main memory = 2^32 bytes. Size of cache = 1024 bytes…
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A: Given information: - memory address is: (0DB63)16
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A: I have answered this question in step 2.
Q: Suppose a computer using direct-mapped cache has 232 bytes of byte-addressable main memory and a…
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Q: Suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and a…
A: Size of main memory = 224 bytes Size of cache= 128 bytes = 27 bytes Size of each block= 64 bytes =…
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A: A) Total number of blocks in main memory = 2^22/2^4 = 2^18 B) Size of offset field =log(block size)…
Q: Suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and a…
A: Offset bits = log (2^6) = 6 bits.
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A: Solution:-
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A: First of all, we need to determine what the index bits are and from above we know the offset is 9…
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Q: Suppose a computer using direct mapped cache has 4G Bytes of main memory and a cache of 256 Blocks,…
A: refer to step 2 for the answer.
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A: Answer is in next step.
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A: Introduction :Size of cache = 16 KB valid bit field = 1 bit Block size = 4 word Size of address = 32…
Q: Suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and a…
A: Please find the answer to the above question below:
Q: Consider a machine with a byte addressable main memory of 216 bytes and block size of 8 bytes.…
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A: a computer using a direct - mapped cache has 232 bytes of byte - addressable main memory cache…
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Q: Suppose a computer using fully associative cache has 224 words of main memory and a cache of 512…
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Q: 5. suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory…
A: Given: 5. suppose a computer using fully associative cache has 224 bytes of byte-addressable main…
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A: CPU would be represented using 32 bits. Cache memory size = 16 MB = 224 B Block size = 8*4 B = 25 B.…
Q: Consider a machine with a byte addressable main memory of 216 bytes and block size of 8 bytes.…
A:
Q: Consider a direct mapping cache of size 32KB with block size of 32 bytes. The CPU generates 32 bit…
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A: required:
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A: How many blocks of main memory are there? => Block size 16 bytes = 2⁴ bytes…
Q: Suppose a computer using fully associative cache has 220220 words of main memory and a cache of 128…
A: solution:
Q: Suppose a computer using direct-mapped cache has 232 bytes of byte-addressable main memory and a…
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Q: Suppose a computer using direct-mapped cache has 232 bytes of byte-addressable main memory and a…
A: Introduction of Cache Mapping: A cache is the fastest memory and used to increase the speed of the…
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- Suppose a byte-addressable computer using set-associative cache has 216 bytes of main memory and a cache of 32 blocks, and each cache block contains 8 bytes.Q.) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache; that is, what are the sizes of the tag, set, and offset fields?Suppose a computer using direct-mapped cache has 232 (that's 232)232) bytes of byte-addressable main memory, and a cache size of 512 bytes, and each cache block contains 64 bytes. How many blocks of main memory are there? What is the format of a memory address as seen by cache, i.e. what are the sizes of the tag, block, and offset fields? To which cache block will the memory address 0x13A4498A map?A cache is set up with a block size of 32 words. There are 64 blocks in cache and set up to be 4-way set associative. You have byte address 0x8923. Show the word address, block address, tag, and index Show each access being filled in with a note of hit or miss. You are given word address and the access are: 0xff, 0x08, 0x22, 0x00, 0x39, 0xF3, 0x07, 0xc0.
- Question 18 Suppose we have a byte-addressable computer using 2-way set associative mapping with 16-bit main memory addresses and 32 blocks of cache. Suppose also that each block contains 8 bytes. The size of the block offset field is bits, the bits. size of the set field is bits, and the size of the tag hield isSuppose a computer using fully associative cache has 220220 words of main memory and a cache of 128 blocks, where each cache block contains 16 words. (a) How many blocks of main memory are there? (b) What is the format of a memory address as seen by the cache, that is, what are the sizes of the tag and word fields? (c) To which cache block will the memory reference 01D872_{16}01D872_{16} map?Suppose a computer using direct-mapped cache has 232 bytes of byte-addressable main memory and a cache of 1024 blocks, where each cache block contains 32 bytes.Q.) What is the format of a memory address as seen by the cache; that is, what are the sizes of the tag, block, and offset fields?
- For a direct-mapped cache design with 64-bit addresses, the following bits of the address are used to access the cache: Tag Index Offset 63-13 12-4 3-0 a. What is the cache block size (in bytes)?b. What is the cache size (in bytes)?c. What is the total number of bits (including valid bit, tag bits and data array bits) to implement this cache?d. For the same block and cache sizes, you want to implement a 4-way set-associative cache, what is the number of index bit and the number of tag bits?Q: A digital computer has a memory unit of 64k * 16 and a cache memory of 1k words. The cache uses direct mapping with a block size of 4 words. i) How many bits are there in the tag, index, block & words fields of the address formats. ii) How many bits are there in each word of cache? iii) How many blocks can the cache accommodate?Suppose a computer using direct mapped cache has 232 byte of byte-addressable main memory, and a cache of 1024 blocks, where each cache block contains 32 bytes. a) How many blocks of main memory are there? b) What is the format of a memory address as seen by the cache, i.e., what are the sizes of the tag, block, and offset fields? c) To which cache block will the memory address 0x000063FA map?
- Q: A digital computer has a memory unit of 64k * 16 and a cache memory of 1k words. The cache uses direct mapping with a block size of 4 words. i) How many bits are there in the tag, index, block & words fields of the address formats.ii) How many bits are there in each word of cache? iii) How many blocks can the cache accommodate? Note: this question is related from computer architecture subject kindly solved this correctly and completly.Suppose a computer using fully associative cache has 224 words of main memory and a cache of 512 blocks, where each cache block contains 16 words. How many blocks of main memory are there? What is the format of a memory address as seen by the cache, i.e., what are the sizes of the tag and offset fields? To which cache block will the memory reference 17042416 map?3. The table below represents five lines from a cache that uses fully associative mapping with a block size of 8. Identify the address of the shaded data, 0xE6, first in binary and then in hexadecimal. The tag numbers and word id bits are in binary, but the content of the cache (the data) is in hexadecimal. Word id bits Tag 000 001 010 011 100 101 110 111 ------------------------------------------ 1011010 10 65 BA 0F C4 19 6E C3 1100101 21 76 CB 80 D5 2A 7F B5 0011011 32 87 DC 91 E6 3B F0 A6 1100000 43 98 ED A2 F7 4C E1 97 1111100 54 9A FE B3 08 5D D2 88