A certain two dimensional shape has the following integrals f dA = 4.5 in² fx dA fyd A S x² dA 13.5 in ³ 13.5 in ³ = 42.75 in4 fxy dA = 39.375 in 4 fy² dA = 42.75 in 4 where dA is a differential area element, dx*dy. Find the following properties of the shape Centroid = (X,Y)= ( 3 3) in. The Area Moments of Intertia about axes parallel to the x and y axes through the centroid. |x' = in4 in4 ly¹ = [ Product of Inertia, Ix'y' = Polar Moment of Inertia, J(x',y') 4

A certain two dimensional shape has the following integrals f dA = 4.5 in² fx dA fyd A S x² dA 13.5 in ³ 13.5 in ³ = 42.75 in4 fxy dA = 39.375 in 4 fy² dA = 42.75 in 4 where dA is a differential area element, dx*dy. Find the following properties of the shape Centroid = (X,Y)= ( 3 3) in. The Area Moments of Intertia about axes parallel to the x and y axes through the centroid. |x' = in4 in4 ly¹ = [ Product of Inertia, Ix'y' = Polar Moment of Inertia, J(x',y') 4

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

36- O A) 30 i- 19 k Nm B) 30 i+9k Nm C) 30 j-9k Nm O D) 12i+30j-9k Nm O E) 9j+30 k Nm
Consider for the part in the figure below, a = 106, b =60 and c =112. 80 20 45 Dimensions in mm Analyze the part in order to calculate the coordinates of the centre of gravity in the (r, y, z) system of coordinates. It is assumed that the following process was following for the manufacturing process • Part 1(a cubic piece of dimension 51 x 60 x 60 is cut out of a Part 2 of dimensions 157 x 60 x 80 and then • Part 3 (triangular prism) is welded Part 2 Fill inN K IA with coordinates of centers of respective parts in mm Yi Vi
Write down the homogeneous transformations AT & T for the frames shown in Fig.2 Fig.2 Ŷ₁ 30⁰ ZA XA Ŷc XB & Xc 2B 2c ŶB 2
A docs.google.com In circular motion vr=0 vr=v theta vr=-v theta ar=0 The right representation of r-theta ***I' coordinates is --- a b. d a O b According to the figure, the vector 25 points equation is
For the area shown in the figure below, OAC is the area of a sector with center at C and radius OC=AC=4*sqrt(2)~5.657 units. This is part 1. Part 2 is the triangle COD. Part 3 is the triangle CAB. Determine, using the method of composite areas, the second moments of area of part 1 about the y-axis [units^4]. Determine, using the method of composite areas, the second moments of area of part 2 about the y-axis [units^4]
* ifr = 8 sec0 then the cartesian equation is %D X^2+y^2=8 O Non of the above O y=8 (x-1)^2+y^2=64 O x=8 O
m and n are orthogonal vectors. Let their component forms be defined as (mx, my) and (nx, ny) respectively, where all values are integers. mx+nx=-3 and nymy=40. If O
Need help expressing the following in Cartesian form: w = j + e^(j)
4.15. Calculate I,, ly, Iy for the section of Figure P4.9 above. You can use the results from Example B.1.
Resolve for the x and y component of F3. y F3%3D650 N 3) F, = 750 N %3D 45° F = 900 N X component of F3: [Choose] y component of F3: [ Choose ]
Answer the following question considering the following 3D vector field F: (Hint: You may need to remember properties of div and/or curl operations mentioned at the end of notes given in Week &8) F (x, y, z) = zx i + eY j + xyz² k Can F be the curl of another vector field? Why? Why not?
ihài 25 Q3) Let vector A = 5i +2j, Vector B = -3i %3D -5j, and vector C = A+ B. (a) Write %3D vector C in component form. (b) Draw a coordinate system and on it show the all vectors. (c) What are the ?magnitude and direction of vector C