A combinational circuit has three inputs (C,l1, 1,) and two outputs (01,00). The function is implemented as the following: If C = 0, then 0,0, becomes I, I9. If C = 1, then O,0, becomes (1,1)+1. For example, if C = 1 and I,lo is 01, 0,0, becomes |10. Note that, if I, I, is 11 and = 1 , then the output value wraps around 00, without any overflow. C The Boolean expression for 01 and 00 and in sum of minterms form are: Select one: O a. 01 = E(1,3,5,6) 0o = E(2,3,4,5) On 0-Σ (2,3,5,6) 0,Σ(1,3,4,6) ο.0Σ (1,3,5,6) 0,Σ(2,3,4, 5) O d. None of the above. %3D
A combinational circuit has three inputs (C,l1, 1,) and two outputs (01,00). The function is implemented as the following: If C = 0, then 0,0, becomes I, I9. If C = 1, then O,0, becomes (1,1)+1. For example, if C = 1 and I,lo is 01, 0,0, becomes |10. Note that, if I, I, is 11 and = 1 , then the output value wraps around 00, without any overflow. C The Boolean expression for 01 and 00 and in sum of minterms form are: Select one: O a. 01 = E(1,3,5,6) 0o = E(2,3,4,5) On 0-Σ (2,3,5,6) 0,Σ(1,3,4,6) ο.0Σ (1,3,5,6) 0,Σ(2,3,4, 5) O d. None of the above. %3D
Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Transcribed Image Text:A combinational circuit has three inputs (C,I,,Io) and two
outputs (01, 00). The function is implemented as the following:
If C = 0, then 0,0, becomes I, Io. If C = 1, then 0,0, becomes
(1o1)+1. For example, if C = 1 and I,1o is 01, 0,00 becomes
|10. Note that, if I, I, is 11 and = 1 , then the output value wraps
around 00, without any overflow.
C
The Boolean expression for 01 and 00 and in sum of minterms fom are:
Select one:
oa0 Σ(1,3,5,6) 00-Σ(2,3,4,5)
O 0Σ (2,3,5,6) 0,Σ(1,3,4,6)
00-Σ(1,3,4,6)
o c
O . 01 = E(1,3,5,6) 0, = E(2,3,4,5)
a. None of the above.
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