A constant applied force F, of 15.0 N pushes a box with a mass m = 6.00 kg a distance x = 15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150.

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Chapter5: Newton's Law Of Motion
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A constant applied force F, of 15.0 N pushes a box with a mass m = 6.00 kg a distance x = 15.0 m across a level floor. The
coefficient of kinetic friction between the box and the floor is 0.150.
F,
m
Assuming that the box starts from rest, what is the final velocity vf of the box at the 15.0 m point?
Uf =
m/s
If there were no friction between the box and the floor, what applied force Fnew Would give the box the same final velocity?
Fnew =
N
Transcribed Image Text:A constant applied force F, of 15.0 N pushes a box with a mass m = 6.00 kg a distance x = 15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150. F, m Assuming that the box starts from rest, what is the final velocity vf of the box at the 15.0 m point? Uf = m/s If there were no friction between the box and the floor, what applied force Fnew Would give the box the same final velocity? Fnew = N
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