A continuous-time signal has the bilateral Laplace transform 1 F,(s) 1 -3 < Re(s) < 3. Then f(t) is s-4 -3t s-3 s+3' u(t) – 2e-3t u(-t) + e“ u(-t) + e*t B. 2e-3t u(t) + e³t u(t) – et u(-t) | С. е -3t u(-t) + et u(-t) u(t) + e³t u(t) – e3t -3t -3t D. 2e - e3t u(-t) – et u(-t) | Е. е u(t) + 2e³t u(-t) + e* u(-t)

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Signal and System Analysis
A continuous-time signal has the bilateral Laplace transform
1
F,(s):
s-4
Re(s) < 3. Then f(t) is
3 <
s-3
s+3'
-3t
А. е
u(t) – 2e-3t
u(-t) + e*t u(-t)
B. 2e-3t u(t) + e3t u(t) – et u(-t)
u(t) + e³t u(-t) + e** u(-t)
u(t) – et u(-t) – et u(-t)
u(t) + 2ešt u(-t) + e* u(-t)
on
-3t
С. е
D. 2e
-3t
-3t
E. e
O I.A.
O II. B
O II. C
O IV. D
OV.E
Transcribed Image Text:A continuous-time signal has the bilateral Laplace transform 1 F,(s): s-4 Re(s) < 3. Then f(t) is 3 < s-3 s+3' -3t А. е u(t) – 2e-3t u(-t) + e*t u(-t) B. 2e-3t u(t) + e3t u(t) – et u(-t) u(t) + e³t u(-t) + e** u(-t) u(t) – et u(-t) – et u(-t) u(t) + 2ešt u(-t) + e* u(-t) on -3t С. е D. 2e -3t -3t E. e O I.A. O II. B O II. C O IV. D OV.E
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