Q1: Secret Messages Implement a Caesar cipher to encrypt messages. a) Create a new Jupyter Notebook and start your program by asking the user fora text to encode and the shift value. Then begin the structure of your programby entering in this loop (we'll build on it more in a bit):encoded Text = ""for letter in text:encoded Text = encoded Text + letterWhat does this loop do? Make sure you understand what the code does beforemoving on!b) Now modify the program above to replace all the alphabetic characters with'x'. For example:Enter text to encrypt: Mayday! Mayday!Enter shift value: 4The encoded phrase is: Xxxxxx! Xxxxxx!c) Now modify your code, we are going to apply the cipher only to the alphabeticcharacters and we will ignore the others. So, your program needs to producethe encoded string using the cipher algorithm with the shift value entered bythe user. Let's see how one might do a cyclic shift. Let's say we have thesequence:012345If we use a shift value of 4 and just shift all the numbers, the result will be:456789Page 3 of 5We want the values of the numbers to remain between 0 and 5. To do this wewill use the modulus operator. The expression x%y will return a number in therange 0 to y-1 inclusive, e.g. 4%6 = 4, 6 % 6 = 0, 7% 6 =1. Thus, the result of theoperation will be:450123Hint: Note that the ASCII value of 'A' is 65 and 'a' is 97, not 0. So, you will haveto think how to use the modulus operator to achieve the desired result. Applythe cipher separately to the upper- and lower-case letters.Here is what you program should output:Enter your text to Encrypt: Mayday! Mayday!Enter your encryption key number (1-26): 4The encrypted message is: Qechec! Qechec!d) Finally, modify your program to decrypt the ciphertext back to the plaintext.(Decryption is the opposite of encryption).

Caesar cipher: Caesar cipher is the type of substitution cipher in which all the letters in the…

a) Create a new Jupyter Notebook and start your program by asking the user for a text to encode and the shift value. Then begin the structure of your program by entering in this loop (we'll build on it more in a bit): encoded Text = *** for letter in text: encoded Text = encoded Text + letter What does this loop do? Make sure you understand what the code does before moving on!

a) Create a new Jupyter Notebook and start your program by asking the user for a text to encode and the shift value. Then begin the structure of your program by entering in this loop (we'll build on it more in a bit): encoded Text = *** for letter in text: encoded Text = encoded Text + letter What does this loop do? Make sure you understand what the code does before moving on!

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter5: Repetition Statements

Section5.6: Nested Loops

Problem 2E

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Please help me find the C CODE for this problem. Thank you! 4. A Shorter Three by CodeChum Admin Numbers in threes are awesome! But the one last time was too lengthy to look at, so I just want to view it in a shorter but still readable format. You okay with this task? Instructions: Print out all numbers from 1 to 100 that is divisible by 3 using a for loop just like the last problem, but this time, with each number only separated by the space like that of the sample output. Output A line containing integers divisible by 3 separated by a space. 3 6 9 12 15 18 21 24...
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