A flywheel whose moment of inertia / = 200 lb-ft² is spinning at 220 RPM. For a flywheel, KE = Iw²/2, where w is the angular velocity, rad/s. Let g = 32.2 ft/s². Step 1 * Your answer is incorrect. How high above the surface of the earth, in ft, would a 70 lb mass have to be raised to have its potential energy equal to the kinetic energy of the flywheel? h = i 20.60 Hint Save for Later ft 4 Attempts: 1 of 4 used Submit Answer

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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A flywheel whose moment of inertia / = 200 lb-ft² is spinning at 220 RPM. For a flywheel, KE = Iw²/2, where w is the angular velocity,
rad/s. Let g = 32.2 ft/s².
Step 1
* Your answer is incorrect.
How high above the surface of the earth, in ft, would a 70 lb mass have to be raised to have its potential energy equal to the kinetic
energy of the flywheel?
h = i 20.60
Hint
Save for Later
ft
A
Attempts: 1 of 4 used Submit Answer
Step 2
The parts of this question must be completed in order. This part will be available when you complete the part above.
Transcribed Image Text:A flywheel whose moment of inertia / = 200 lb-ft² is spinning at 220 RPM. For a flywheel, KE = Iw²/2, where w is the angular velocity, rad/s. Let g = 32.2 ft/s². Step 1 * Your answer is incorrect. How high above the surface of the earth, in ft, would a 70 lb mass have to be raised to have its potential energy equal to the kinetic energy of the flywheel? h = i 20.60 Hint Save for Later ft A Attempts: 1 of 4 used Submit Answer Step 2 The parts of this question must be completed in order. This part will be available when you complete the part above.
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Follow-up Question
A flywheel whose moment of inertia / = 200 lb-ft² is spinning at 220 RPM. For a flywheel, KE = Iw²/2, where w is the angular velocity,
rad/s. Let g = 32.2 ft/s².
Step 1
How high above the surface of the earth, in ft, would a 70 lb mass have to be raised to have its potential energy equal to the kinetic
energy of the flywheel?
h = 23.547
Hint
Your answer is correct.
Step 2
h = i
How high above the surface of the earth, in ft, would a 110 lb mass have to be raised to have its potential energy equal to the
kinetic energy of the flywheel?
eTextbook and Media
ft
Save for Later
Attempts: 2 of 4 used
ft
Attempts: 0 of 4 used Submit Answer
Transcribed Image Text:A flywheel whose moment of inertia / = 200 lb-ft² is spinning at 220 RPM. For a flywheel, KE = Iw²/2, where w is the angular velocity, rad/s. Let g = 32.2 ft/s². Step 1 How high above the surface of the earth, in ft, would a 70 lb mass have to be raised to have its potential energy equal to the kinetic energy of the flywheel? h = 23.547 Hint Your answer is correct. Step 2 h = i How high above the surface of the earth, in ft, would a 110 lb mass have to be raised to have its potential energy equal to the kinetic energy of the flywheel? eTextbook and Media ft Save for Later Attempts: 2 of 4 used ft Attempts: 0 of 4 used Submit Answer
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