A force É = (7.10N)i + (4.00 N)ĵ + (5.00 N) k acts on a 1.70 kg mobile object that moves from an initial position of d; = (3.70 m) î + (8.10 m)ĵ + (2.00 m) k to a final position of df = (2.80 m)î + (8.50m)ĵ +(4.40 m) k in 1.70 s. Find (a) the work done on the object by the force in the 1.70 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors d; and df. (a) Number 38.8 Units (b) Number Units 22.8 (c) Number Units (degrees) 12.43

University Physics Volume 1
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Chapter5: Newton's Law Of Motion
Section: Chapter Questions
Problem 77AP: (a) Find an equation to determine the magnitude of the net force required to stop a car of mass m,...
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Chapter 07, Problem 051
| Your answer is partially correct. Try again.
A force F = (7.I0N)? + (4.00 N)ĵ + (5.00 N) k acts on a 1.70 kg mobile object that
moves from an initial position of di
: (3.70 m) î + (8.10 m)ĵ + (2.00 m) ê to a final
=
position of áf = (2.80 m)î + (8.50 m)} + (4.40 m) k in 1.70 s. Find (a) the work
done on the object by the force in the 1.70 s interval, (b) the average power due to the
force during that interval, and (c) the angle between vectors d; and df.
a dj.
(a) Number
Units
38.8
(b) NumberT22.8
Units
(c) NumberT12.43
UnitsTo (degrees)
Click if you would like to Show Work for this question: Open Show Work
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Transcribed Image Text:Chapter 07, Problem 051 | Your answer is partially correct. Try again. A force F = (7.I0N)? + (4.00 N)ĵ + (5.00 N) k acts on a 1.70 kg mobile object that moves from an initial position of di : (3.70 m) î + (8.10 m)ĵ + (2.00 m) ê to a final = position of áf = (2.80 m)î + (8.50 m)} + (4.40 m) k in 1.70 s. Find (a) the work done on the object by the force in the 1.70 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors d; and df. a dj. (a) Number Units 38.8 (b) NumberT22.8 Units (c) NumberT12.43 UnitsTo (degrees) Click if you would like to Show Work for this question: Open Show Work Question Attempts: 1 of 10 used SUBMIT ANSWER SAVE FOR LATER
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