A force É = (7.10N)i + (4.00 N)ĵ + (5.00 N) k acts on a 1.70 kg mobile object that moves from an initial position of d; = (3.70 m) î + (8.10 m)ĵ + (2.00 m) k to a final position of df = (2.80 m)î + (8.50m)ĵ +(4.40 m) k in 1.70 s. Find (a) the work done on the object by the force in the 1.70 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors d; and df. (a) Number 38.8 Units (b) Number Units 22.8 (c) Number Units (degrees) 12.43
A force É = (7.10N)i + (4.00 N)ĵ + (5.00 N) k acts on a 1.70 kg mobile object that moves from an initial position of d; = (3.70 m) î + (8.10 m)ĵ + (2.00 m) k to a final position of df = (2.80 m)î + (8.50m)ĵ +(4.40 m) k in 1.70 s. Find (a) the work done on the object by the force in the 1.70 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors d; and df. (a) Number 38.8 Units (b) Number Units 22.8 (c) Number Units (degrees) 12.43
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter5: Newton's Law Of Motion
Section: Chapter Questions
Problem 77AP: (a) Find an equation to determine the magnitude of the net force required to stop a car of mass m,...
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