A) Linear velocity: LT¹¹ V=U + at = 0+1 * 0.5 = 0.5m/s LT-¹= LT 2x T SI unit of distance is metre, Velocity has the SI unit of metre/second. Hence the answer of 0.5m/s. B) Linear Acceleration: LT-2 a = V-U t 0.5-0 0.5 = C) Final Angular velocity: 7²¹ w = d 0.5m/s 0.4 D) Angular acceleration of the drum: 7² a 1 = R 0.4 1m/s² V = = 1.25 rad/s = 2.5 rad/s E) The tension force in the cable: MLT-² MA = Mg - T = T = M(ga) = T = 3(9.8 - 1) = 29.43 = 26.4N F) The torque applied to the drum: ML²T-² t = Tr = 26.4 * 0.4 = 10.56Nm
Angular speed, acceleration and displacement
Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.
Angular Position
Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.
what are the equations of dimensional analysis for the attched sheet.
I think A) linear velocity is LT^-1= LT^-2*T
Can you please advise for (A,B,C,D,E,F) of the attached sheet
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