A local authority is considering three alternatives access plans. The capital budget will only allow accepting one of the three alternatives. Financial data for the three plans are given in Table 2. The interest is 11%, compounded annually. i) Evaluate the three plans based on the present worth method of comparison. ii) Propose your opinion to accept the best plan. Table 2 Plan Plan 1 Plan 2 Plan 3 First cost (RM) 3,000,000 3,450,000 2,500,000 Estimated annual Revenue (RM) 550,000 560,000 450,000 Estimated salvage value (RM) 40,000 45,000 30,000 Useful life 11 13 10
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- 2. If the rate of return on the additional cash flows between the two alternatives is less than the MARR rate, which alternative should be chosen? A. The alternative to choose is one that requires a lower initial investment B. The alternative chosen is the alternative with the smallest annual cost c. The alternative chosen is the alternative with the highest annual cost D. The alternative chosen is an alternative with an annual fee equal to the initial fee Please solve based the option max 20 minutes ASAPThe cash flows for three mutually exclusive alternatives are given in table below. MARR = 4%. ALB Alt. C 27,000 24,000 7,600 6,500 13% 11% Initial cost Annual benefits ROR Life in years Alt. A $15,000 $4,500 15% 5 Reference: Case Study 8 The best alternative for a MARR of 2.0% using the incremental rate of return analysis is A. Alt. C B. Alt. B C. Alt. A OD.Do-nothingQuestion 4 Which increment should be examined first in incremental rate of return analysis, if MARR = 9.0%? Do-nothing A First cost Annual benefit Life ROR A-B O A-C O B-C OB-A 0 0 10 yrs $5,500 895 10.0% B C $3,000 $7,000 531 1,164 12.0% 10.5% D $3,000 408 6.0%
- Solve by incremental cashflow then PW = 0. To get the value of i by interpolation. Problem 3: Two plans for a hydroelectric project in Peru have been proposed. The opportunity cost, in soles, of resources is 10 percent. Data on the two alternatives are: System First cost ($/,000,000,000) 300 160 Economic life (years) 40 20 Salvage value ($/,000,000,000) 15 12 Annual benefits (S/.000,000,000) 25 22 Annual costs ($/,000,000,000) 3 1 Using the internal rate of return method, which of the two systems should be chosen or should either be selected?Would love some help on how to approach this - thanks! The cash flows for three different alternatives are given in table below. MARR =10%. Alt. A Alt. B Alt. C Initial cost $5,000 9,000 7,500 Annual benefits $1,457 2,518 2,133 RoR 14% 13% 12.4% Life in years 5 1. ΔRoR for the first increment (Alt. C-Alt. A) is ___________________. A.10.12% B. 9.38% C. 11.85% D. 11.00% 2. ΔRoR for the second increment is ___________________. A. 10.12% B. 9.38% C. 8.94% D. 9.87% 3. The best alternative for a MARR of 10% using the incremental rate of return analysis is ____________. A. Alt. C B. Alt. A C. Alt. B D. Do nothing:[A] { > Incremental analysis ([ B Alternative], [B wins ]): C A company considering 2 different machines at MARR at 12% Both life spans = 10 years Initial Cost Annual Operating lost Benefits per yin ar Salvage Value \table MM If you are and of frying investment to company decide More than 2 alternatives if the additional increment is worth while, compare Alternative: A Incremental analysis (Alternative) pairs then B C A MARR Company at Considering 2 different machines at 12% Both life spans = 10 years. M/C X м/с у Initial Cost 160000 285000 Annual Operating Cost Benefits per year Salvage Value 45 000 90000 45000 105000 20000 40000
- What is the best alternative using incremental Analysis? Use MARR = 15% A B C Capital Investment $ 2,000 7,000 4,200 Annual Revenues 3,200 8,000 6,000 Аппиal Costs 2, 100 5, 100 4,000 Market Value at the end of useful life 100 600 420 Useful Life (in years) 10 10 10 The correct ranking of Alternative is Blank 1 Select Alternative Blank 2 Note: Do not put comma, unit of measure and limit your answer to two decimal places. Ex: A-B-CA project is being planned that has an initial investment at time 0, annual revenuesand expenses, and a salvage value at the end of the project lifespan (20 years). The financialvalues are summarized below:Initial investment amount at time 0 $150,000Estimated annual revenue $34,500 per yearEstimated annual expenses $8,700 per yearEstimated salvage value at end of lifespan $10,000Minimum attractive rate of return (MARR) 15%a. Calculate the capital recovery amount CR(i%).b. Using the annual worth (AW) method, determine whether purchasing the equipmentis economically justified.c. Repeat part (a) using the internal rate of return (IRR) method based on annual worth(AW).d. Using the present worth (PW) method, determine the break-even time period afterwhich purchase of the equipment generates a profit. (Find N when PW = 0) year period.Sebastian is about to compare a set of mutually exclusive and indivisible alternatives using a ranking approach. Which of the following is not an appropriate measure of worth? a. Present worth b. Annual worth c. Future worth d. Internal rate of return
- For this problem, consider the five mutually exclusive investment alternatives, A through E, with incremental analysis. Do nothing is not an alternative. |A C Capital $55,000 $90,000 $45,000 $30,000 $70,000 investment Annual $30,000 $40,000 $25,000 $15,000 $35,000 expenses Annual $50,000 $52,000 $38,000 $29,000 $45,000 revenues Market value at $10,000 $15,000 $10,000 $11,000 $15,000 ΕΟΥ 10 IRR ??? 7.4% 26.7% 46.0% 9.2% Useful Life in 10 |10 10 10 10 years When applying incremental analysis, the base alternative is identified, and then the first incremental comparison should be which of the following? Assume the MARR=10%. Choose the correct answer below. The first letter is the base alternative and the second letter is the next alternative in the analysis. A. D - C В. Е - D C. E - A D. D - B E. D - A7) Margaret has a project with a $28 000 first cost that returns $5000 per year over its 10-year life. It has a salvage value of $3000 at the end of 10 years. If the MARR is 15 percent, what is the present worth of this project?Alternatives B and C are replaced at the end of their useful lives with identical replacements. Find the best alternative using MARR = 10%. Data Initial Cost Uniform Annual Benefit Useful Life a) Benefit to Cost ratio analysis b) Payback Period Analysis Alt. A $6,00 $150 20 Alt. B $900 $300 5 Alt. C $1,800 $450 10