A mass of 0.2 kg stretches a spring by 20 cm. The damping constant is c = 0.4. External vibrations create a force of F(t) = 0.2 cos 8t N. Find the steady-state solution. O "P up == Up = Up = 15 481 15 481 15 481 15 481 cos 8t + cos 8t - cos 8t - cos 8t + 16 481 16 481 16 481 16 481 sin 8t sin 8t sin 8t sin 8t
A mass of 0.2 kg stretches a spring by 20 cm. The damping constant is c = 0.4. External vibrations create a force of F(t) = 0.2 cos 8t N. Find the steady-state solution. O "P up == Up = Up = 15 481 15 481 15 481 15 481 cos 8t + cos 8t - cos 8t - cos 8t + 16 481 16 481 16 481 16 481 sin 8t sin 8t sin 8t sin 8t
Related questions
Question
Transcribed Image Text:A mass of 0.2 kg stretches a spring by 20 cm. The damping constant is c = 0.4. External vibrations
create a force of F(t) = 0.2 cos 8t N. Find the steady-state solution.
O
O
up
==
Up
up
=
"P
15
481
15
481
15
481
15
481
cos 8t +
cos 8t -
cos 8t -
cos 8t +
16
481
16
481
16
481
16
481
sin 8t
sin 8t
sin 8t
sin 8t
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 2 images
