A perfectly reflecting flat mirror is uniformly illuminated by light striking it perpendicularly. The area of the mirror is 2.09 m² and the light exerts a force of 1.91 μN on it. Calculate the intensity I of the light. I = W/m²
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- The electric field of an electromagnetic wave traveling in vacuum is described by the following wave function: E =(5.00V/m)cos[kx(6.00109s1)t+0.40] j where k is the wavenumber in rad/m, x is in m, t s in Find the following quantities: (a) amplitude (b) frequency (c) wavelength (d) the direction of the travel of the wave (e) the associated magnetic field waveA device called an insolation meter is used to measure the intensity of sunlight. It has an area of 100 cm2 and registers 6.50 W. What is the intensity in W/m2?What is the intensity of an electromagnetic wave with a peak electric field strength of 125 Vim?
- The electric part of an electromagnetic wave is given by E(x, t) = 0.75 sin (0.30x t) V/m in SI units. a. What are the amplitudes Emax and Bmax? b. What are the angular wave number and the wavelength? c. What is the propagation velocity? d. What are the angular frequency, frequency, and period?A perfectly reflecting flat mirror is uniformly illuminated by light striking it perpendicularly. The area of the mirror is 2.43 m2and the light exerts a force of 1.03 μN on it. Calculate the intensity ? of the light. ?=???A traveling electromagnetic wave in a vacuum has an electric field amplitude of 92.9 V/m. Calculate the intensity S of this wave. Then, determine the amount of energy U that flows through area of 0.0279 m? over an interval of 18.1 s, assuming that the area is perpendicular to the direction of wave propagation. S = W/m? U = J
- A traveling electromagnetic wave in a vacuum has an electric field amplitude of 73.3 V/m. Calculate the intensity S of this wave. Then, determine the amount of energy U that flows through area of 0.0249 m² over an interval of 16.1 s, assuming that the area is perpendicular to the direction of wave propagation. S = W/m? U J * TOOLS x10A traveling electromagnetic wave in a vacuum has an electric field amplitude of 77.3 V/m. Calculate the intensity S of this wave. Then, determine the amount of energy U that flows through area of 0.0273 m² over an interval of 11.7 s, assuming that the area is perpendicular to the direction of wave propagation. S = U = W/m² JA sinusoidal electromagnetic wave propagates in the +x direction through empty space. Its electric field is described by E = (9.71E4 V/m) × sin ((2.06E11 rad/s) t – (687 rad/m) x ) . What is the average intensity of this electromagnetic wave (in W/m2)?
- The electric field of an electromagnetic wave is given by 2.0 sin(kz - wt) i +8.0 sin(kz - wt) j. If the wave is propagating in the - direction, find the direction of the magnetic field when sin(kx - wt) is negative. O 0.241 -0.971 O 0.971 -0.241 O -0.971 +0.241 -0.241 +0.971Sunlight, with an intensity of 643 W/m², strikes a flat collecting surface perpendicularly and is totally absorbed. The area of the surface is 8.55 m². What is the force F in micronewtons that acts on the surface due to the sunlight? F = μεThe intensity of light from a source is inversely proportional to its square of the distance from the source. If a pocketbook is 2.4 m from the lamp, the illumination on the page of the book is 500 lm/m2 (lumens per square meter). How far must the lamp be moved so that the intensity of light will be doubled?