A R-load half-wave rectifier used sinusoidal voltage source with a peak value (35.353kV). The firing angle is (30°). The total resistance is 50k2 and frequency is 50HZ. Calculate (in details): load direct voltage, maximum direct voltage, normalized voltage and effective voltage, power delivered to the load, power factor, form factor. ripple factor?

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter12: Electronic Control Devices
Section: Chapter Questions
Problem 4RQ: What is the difference between a diode and rectifier?
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A R-load half-wave rectifier used sinusoidal voltage source with a peak value
(35.353kV). The firing angle is (30). The total resistance is 50k2 and frequency is
50HZ. Calculate (in details): load direct voltage, maximum direct voltage,
normalized voltage and effective voltage, power delivered to the load, power factor,
form factor, ripple factor?
Transcribed Image Text:A R-load half-wave rectifier used sinusoidal voltage source with a peak value (35.353kV). The firing angle is (30). The total resistance is 50k2 and frequency is 50HZ. Calculate (in details): load direct voltage, maximum direct voltage, normalized voltage and effective voltage, power delivered to the load, power factor, form factor, ripple factor?
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