A ray of light strikes a flat glass block at an incidence angle of 8₁ = 39.8°. The glass is 2.00 cm thick and has an index of refraction that equals no = 1.65. 2.00 cm Ⓡ (a) What is the angle of refraction, 82, that describes the light ray after it enters the glass from above? (Enter your answer in degrees to at least 2 decimal places.) (b) with what angle of incidence, 83, does the ray approach the interface at the bottom of the glass? (Enter your answer in degrees to at least 2 decimal places.) (c) with what angle of refraction, 84, does the ray emerge from the bottom of the glass? (Enter your answer in degrees to at least 1 decimal place.)
A ray of light strikes a flat glass block at an incidence angle of 8₁ = 39.8°. The glass is 2.00 cm thick and has an index of refraction that equals no = 1.65. 2.00 cm Ⓡ (a) What is the angle of refraction, 82, that describes the light ray after it enters the glass from above? (Enter your answer in degrees to at least 2 decimal places.) (b) with what angle of incidence, 83, does the ray approach the interface at the bottom of the glass? (Enter your answer in degrees to at least 2 decimal places.) (c) with what angle of refraction, 84, does the ray emerge from the bottom of the glass? (Enter your answer in degrees to at least 1 decimal place.)
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter25: Reflection And Refraction Of Light
Section: Chapter Questions
Problem 16P
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VIEWStep 2: Calculate the angle of refraction that describes the ray after it enters into the block
VIEWStep 3: Calculate the angle of incidence at which the ray approaches the bottom of the glass block
VIEWStep 4: Calculate the angle of refraction at which the ray emerges from the bottom of the glass block
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