The beam in the figure below is subjected to a load P= 4.9 kN at its end. Young's modulus is 210 GPa and the moment of inertia for the beam's cross-section is5×106 mm².A11-1B▸|x₂.bPvcIf a = 1.9 m and b= 0.5 m, determine:a) Reaction value at support A. Positive direction is considered upwards. Enter your answer in kN to 2 decimal places. b) moment equation M(x₁) in the segment AB, where x₁ changes from 0 at support A to a at support B. Enter the equation in terms of variables P, a, b and X₁.Syntax rules for entering equations:adding, subtracting, etc is simply done by entering: +, -, *,/• Variables can be uppercase and lowercase letters, subscripts are recognized, for instance if you type u1 it will be interpreted as ₁example: entering into the answer box a*b^2*x1/2 and clicking Display response button will displayabx₁

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Answered: a) Reaction value at support A.…

Engineering

Civil Engineering

a) Reaction value at support A. Positive direction is considered upwards. Enter your answer in kN to 2 decimal places.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Matrix Algebra for Structural analysis

Structural analysis is a process in which the effects of different loads and internal forces, acting on structures and their elements are determined. This method of analysis is effective in detecting the failure loads of the structural elements and the design can be altered before commencing the construction process, which ensures proper strength and safety of the structures.

Question

100%

The beam in the figure below is subjected to a load P= 4.9 kN at its end. Young's modulus is 210 GPa and the moment of inertia for the beam's cross-section is
5×106 mm².
A
11-1
B
▸
|x₂.
b
P
vc
If a = 1.9 m and b= 0.5 m, determine:
a) Reaction value at support A. Positive direction is considered upwards. Enter your answer in kN to 2 decimal places.

b) moment equation M(x₁) in the segment AB, where x₁ changes from 0 at support A to a at support B. Enter the equation in terms of variables P, a, b and X₁.
Syntax rules for entering equations:
adding, subtracting, etc is simply done by entering: +, -, *,/
• Variables can be uppercase and lowercase letters, subscripts are recognized, for instance if you type u1 it will be interpreted as ₁
example: entering into the answer box a*b^2*x1/2 and clicking Display response button will displayabx₁

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