A recent experiment investigated the relationship between smoking and urinary incontinence. Of the 322 subjects in the study who were incontinent, 113 were smokers, 51 were former smokers, and 158 had never smoked. Of the 284 control subjects who were not incontinent, 68 were smokers, 23 were former smokers, and 193 had never smoked. (Hint- this means there are going to be 3 categories and 2 rows…) a. Create a table displaying this data. (This will be your “Observed” data.) b. What is the expected frequency in each cell? (Need to make the Expected table—remember the null Hyp. is that there is no relationship between smoking and incontinence. The first Exp value will be: 181 x 322/606= 96.17…) c. Conduct a significance test to see if there is a relationship between smoking and incontinence. (Show your work.)  What Chi Square value do you get? What p value do you get? d. What do you conclude?(Remember: Powerpoint slide #20-22)Expected values in chi-sq test of independence: Exp = Column total x Row total / Grand total

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 10CYU
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A recent experiment investigated the relationship between smoking and urinary incontinence. Of the 322 subjects in the study who were incontinent, 113 were smokers, 51 were former smokers, and 158 had never smoked. Of the 284 control subjects who were not incontinent, 68 were smokers, 23 were former smokers, and 193 had never smoked. (Hint- this means there are going to be 3 categories and 2 rows…)

a. Create a table displaying this data. (This will be your “Observed” data.)


b. What is the expected frequency in each cell? (Need to make the Expected table—remember the null Hyp. is that there is no relationship between smoking and incontinence. The first Exp value will be: 181 x 322/606= 96.17…)


c. Conduct a significance test to see if there is a relationship between smoking and incontinence. (Show your work.)

 What Chi Square value do you get? What p value do you get?


d. What do you conclude?
(Remember: Powerpoint slide #20-22)
Expected values in chi-sq test of independence:
Exp = Column total x Row total / Grand total

 

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