Answered: A rigid bar with negligible mass is…

A rigid bar with negligible mass is pinned and attached to two vertical rods. If P = 50 kN, compute the following. a. Stress in the steel rod. b. Stress in the bronze rod.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the steel rod caused by the 42758-Nload, using the following data: length of steel = 1.27 m, length of bronze = 2.06 m Area of steel = 522 mm, Area of bronze = 239 mm Modulus of elasticity of steel = 216 Gpa, Modulus of elasticity of bronze = 84 Gpa x= 0.69 m, y = 1.08 m, and z = 0.86 m. Round off the final answer to three decimal places. ... Bronze Steel Ey te z
The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the bronze rod caused by the 42563-Nload, using the following data: length of steel = 1.56 m, length of bronze = 2.18 m Area of steel = 563 mm, Area of bronze = 233 mm Modulus of elasticity of steel = 193 Gpa, Modulus of elasticity of bronze = 82 Gpa x = 0.69 m, y = 1.03 m, and z = 0.79 m.
The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the bronze rod caused by the 45846-Nload, using the following data: length of steel = 11 m, length of bronze = 2.3 m Area of steel = 562 mm, Area of bronze = 335 mm Modulus of elasticity of steel = 195 Gpa, Modulus of elasticity of bronze = 80 Gpa x= 0.55 m, y = 1.12 m, and z = 0.78 m. Round off the final answer to two decimal places. ... Bronze Steel
The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the bronze rod caused by the 48512-Nload, using the following data: length of steel = 1.42 m, length of bronze = 2.36 m Area of steel = 639 mm, Area of bronze = 319 mm Modulus of elasticity of steel = 180 Gpa, Modulus of elasticity of bronze = 81 Gpa x = 0.58 m, y = 1.13 m, and z = 0.72 m. Round off the final answer to two decimal places.
The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the steel rod caused by the 43091-Nload, using the following data: length of steel = 1.36 m, length of bronze = 2.08 m Area of steel = 562 mm, Area of bronze = 243 mm Modulus of elasticity of steel = 215 Gpa, Modulus of elasticity of bronze = 102 Gpa x = 0.63 m, y = 1.01 m, and z = 0.84 m.
The cable carrying three 400-N loads has a sag at C of hC = 14 m. Calculate the following: 26.1 The magnitude of the tensile force in segment AB is Blank 1 N. 26.2 The magnitude of the tensile force in segment BC is Blank 2 N. 26.3 The magnitude of the tensile force in segment CD is Blank 3 N. 26.4 The magnitude of the tensile force in segment DE is Blank 4 N.
Find the tension of the cord that extends from point C to D and compute for stress experienced by the cable if it's diameter in 1.51 in2. Neglect the members weight and friction. Round-off your answer into the nearest whole number. 150 Ib/ft 6 ft ft 6 ft 12 ft ft ANS: T = Ib, Stress = ksi
A ladder with a uniform cross-section has a length of 4.80-foot long. It weighs W Ib. It is arranged such that one end is on the ground and the other against a vertical wall. The angle of triction at all contact surtaces is 20 degrees. What is the value of the coefficient of triction? What is f, in terms of variable Na? What is the normal force at A in terms of variable W? Answer in three decimal places
Q1: 30-mm-diameter steel bar is to be used as a torsion spring. If the torsional stress in the bar is not to exceed 110 MPa when one end is twisted through an angle of 30°, what must be the length of the bar in m? modulus of rigidity=80 GPa . (close to two decimal)
ENTER YOUR ANSWER THE WAY I SPECIFY HERE IN ADDITION TO DOING IT ON SCRATCH PAPER 400 N 800 N B D A E C 2 m Use the method of sections to calculate the axial force in members AC and BC. Enter your answer in the following way rounded to the nearest whole number. Example If your answer is TAC 2 N tension TBC =3.1 N compression. enter 2Tension;3Compression Enter TAC then TBC (no space)
A round steel bar with a diameter of 1.500 in is subjected to the axial loads shown. P1 = 95 k, P2 = 115 k, P3= 55 k, P4 = (P1-P2+P3) k. If Section 2 has a length, L2 = 65 inches, find the change in length of Section 2. Report the answer below in inches, absolute value, 3 significant digits. P1 Your Answer: 100 inches Round Steel Bar P2 Section 2 12 P3 80 inches P4
A bar, 12 mm in diameter is acted upon by an axial load of 20 kN. The change in diameter is measured as 0.03 mm. DeterminePoisson’s ratioYoung’s modulusBulk modulus Assume modulus of rigidity as 80 GPa