A simple curve of the proposed extension of Mantabahadra Highway have a direction of tangent AB which is due north and tangent BC bearing N45°E. Point A is at the P.C. who stationing is 20 + 130.46. The degree of the curve is 4º. 1.1. Compute the long chord of the curve 1.2. Compute the stationing at point D on the curve along a line joining the center of the curve which makes an angle of 54° with the tangent line passing thru the P.C. 1.3. What is the length of the line from D to the intersection of the tangent AB.

A simple curve of the proposed extension of Mantabahadra Highway have a direction of tangent AB which is due north and tangent BC bearing N45°E. Point A is at the P.C. who stationing is 20 + 130.46. The degree of the curve is 4º. 1.1. Compute the long chord of the curve 1.2. Compute the stationing at point D on the curve along a line joining the center of the curve which makes an angle of 54° with the tangent line passing thru the P.C. 1.3. What is the length of the line from D to the intersection of the tangent AB.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

1. The curve of a diversion road has a tangent “AB” which is directed due North and theother tangent “BC” is having a bearing of ?70°?. Point “A” is located at P.C. whosestationing is 12 + 600. The degree of curve using arc-basis is 5°.a. Compute the radius of the curve.b. Compute the long chord of the curve.c. What is the stationing at P.I.?d. Compute for the middle ordinate.e. Compute for the external distance.
The bearings of forward and backward tangent are N 65°30' E and N 75°40' W, respectively. If the curve is 2° for a full station of 20m and the stationing of the vertex is 12+ 582.50, determine the: Elements of the curve Stationing of P.C and P.T Lengths of sub-chords and its corresponding sub-angles
Given a compound curve Il = 24°, I2 = 36°, D1= 6°, D2 = 4° A. Compute the length of the common tangent of the compound curve. B. Compute the station of P.C if P.I is at sta. 12 +988.20 C. Compute the sta. P.T
A parabolic curve having a forward tangent of -5% intersects a back tangent of 7% at station 10 + 750 whose elevation is 435.8 m. The curve passes through point A whose elevation is 432.15 at sta. 10 + 767.30. determine the length of the curve. a. 240 m b. 250 m c. 260 m d. 270 m
1. A simple curve connects two tangents AB and BC with bearings N 85°30 E and S 68°30' E, respectively. If the stationing at the P.C. is 4+360.20m and degree of curvature is 5°, Compute the: a. Elements of the curve. b. Stationing of P.I. and P.T.
5. A 4-degree simple curve has an angle of intersection of 54o. The PC of the curve is at station 34 + 523. a. Determine the length of the long chord in meters. A. 291.94 C. 318.47 B. 282.57 D. 257.83 b. Determine the length of the curve in meters A. 270 C. 290 B.280 D. 300 c. Determine the stationing of the midpoint of the curve. A. 34 + 848 C. 34 + 688 B. 34 + 658 D. 34 + 618
29. A simple curve connects two tangents AB and BC with bearing N 85°30' E and S 68°30'E respectively. Point D along line AB has an coordinate of 20100 N and 20100 E while point E along line BC has coordinate of 20086.55 N and 20184.27 E. Solve for the degrees of simple curve that shall be tangent to the three lines AB, DE and BC. ANS: 3°04'
1. In the establishment of a simple railway curve, it was found out that it must pass through a point 15 m from the vertex and equidistant from the tangents intersecting at an angle of 28°. The station of the vertex is at 2+880. Find the radius of the curve, the stationing of the beginning and end of the curve and the degree of the curve for a 20-m chord.
Given for a Simple Curve, a. R=750m b. I-34 deg c. STA. V = 20+050 Detemine the Elements of the given Simple Curve. (Use 100m-Stations) i. Degree of the Curve ii. Tangent Distance iii. Length of the Chord iv. Length of the Curve v. Extemal Distance vi. Middle of Ordinate vii. Sta. PC and Sta. PT
Problem No. 1: Two tangents intersect at STA 2+550. A compound curve laid on their tangents has the following data: I1=31deg.;I2=36deg.;D1=3deg.;D2=5deg.; (a) Compute the stationing at PC,PCC and PT
The bearings of forward and backward tangent are N 65°30' E and N 75°40' W, respectively. If the degree of curve is 2° for a full station of 20m and the stationing of the vertex is 12 + 582.50, determine the: a. Elements of the curve b. Stationing of P.C. and P.T. c. Lengths of sub-chords and its corresponding sub-angles
A simple curve of the proposed extension of Mantabahadra Highway have a direction of tangent AB which is due north and tangent BC bearing N 50° E. Point A is at the PC whose stationing is 20+130.46. The degree of curve is 4°. a) Compute the long chord of the curve. b) Compute the stationing of point D on the curve along a line joining the center of the curve which makes an angle of 54° with the tangent line passing thru the PC. c) What is the length of the line from D to the intersection of tangent AB.