A solution prepared in the lab contains 3.5 x 10-4 M Sr² and 0.0010 M F. Will aprecipitate form? (Ksp of SrF₂ is 4.3 x 10-⁹)A) Yes, because Q < Ksp.B) Yes, because Q > Ksp.C) No, because Q < Ksp.D) No, because Q > Ksp

Condition of Precipitation: Ionic product(Q) > solubility product(Ksp)Q = [Sr2+] [F-]2

A solution prepared in the lab contains 3.5 x 10-4 M Sr² and 0.0010 M F. Will a precipitate form? (Ksp of SrF₂ is 4.3 × 10-⁹) A) Yes, because Q< Ksp. B) Yes, because Q > Ksp. C) No, because Q < Ksp. D) No, because Q> Ksp

A solution prepared in the lab contains 3.5 x 10-4 M Sr² and 0.0010 M F. Will a precipitate form? (Ksp of SrF₂ is 4.3 × 10-⁹) A) Yes, because Q< Ksp. B) Yes, because Q > Ksp. C) No, because Q < Ksp. D) No, because Q> Ksp

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter13: An Introduction To Ultraviolet-visible Molecular Absorption Spectrometry

Section: Chapter Questions

Problem 13.12QAP: The equilibrium constant for the reaction 2CrO42+2H+Cr2O72+H2O is 4.2 1014. The molar...

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Mass Spectrometry

This process is an instrumental method in which a sample is changed to fast moving positive ions by electron bombardment. The charged particles vary due to their different mass to charge ratio and are estimated with the help of this difference. It is also called mass spectroscopy.

Question

A solution prepared in the lab contains 3.5 x 10-4 M Sr² and 0.0010 M F. Will a
precipitate form? (Ksp of SrF₂ is 4.3 x 10-⁹)
A) Yes, because Q < Ksp.
B) Yes, because Q > Ksp.
C) No, because Q < Ksp.
D) No, because Q > Ksp

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