Answered: A spring elongates by 1.5 cm because of…

A spring elongates by 1.5 cm because of a force of 15 N. Therefore the spring constant should be O 1000.0 N/m O 10.0 N/m O 100.0 N/m O 10,000.0 N/m

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter6: Energy Of A System

Section: Chapter Questions

Problem 22P

See similar textbooks

Related questions

Q: Tests on a spring showed that 1000-N of force was required to compress the spring 0.5-m. The spring…

A: Given data: The force applied is F=1000 N. The compression in spring is x=0.5 m. The mass of ball…

Q: constant

A: The solution can be given as follows, m is the mass hung on spring g is the acceleration due to…

Q: A 388 g mass is hung on the spring assembly shown below. The mass stretches the springs to…

Q: The spring constant (k) is a measure of Choose from the choices below: the extension of a…

A: We know that, F=-kx So, k=−F/x Dimension of F=[MLT-2] Dimension of x= [L] Therefore, dimension of k=…

Q: A spring hangs vertically next to a ruler. The end of the spring is next to 15 cm mark on the…

A: Given Data: The mass of spring is, m=2.0 kg The spring constant is, k=51 N/m The expression for…

Q: A block is dropped onto a spring with a spring constant of 30 N/m. The block has a speed of 3.3 m/s…

Q: A spring is stretched vertically by 0.50 meters when a 15 kg mass is hung from the spring and the…

A: mass = 15 kg stretching in spring = 0.5 m

Q: block of mass m 3 kg is attached to a spring with spring constant k = 250 N/m. Then it pulled a…

A: Given m = 3 kg

Q: What is the mass on a spring if the periodicity is .55 s and the spring constant is 2.79 N/m m- K+?…

A: Given time period T = 0.55 s spring constant k = 2.79N/m we have to calculate mass of the spring

Q: A 0.35 kg branch falls from a tree onto a trampoline. If the branch was initially 2.6 m above the…

Q: The left end of a spring is attached to a wall. The right end of the spring is attached to a block.…

A: The spring constant, k=26.2 N/m Displacement of the spring in the x-direction, x=11.3 cm

Q: A mass of 10.0 kg is attached to a spring on a frictionless horizontal surface. The spring constant…

Q: . A spring with a spring constant of 25 N/m is stretched 65 cm. What was the force used? 10. A 75 N…

A: Given: 9- spring constant, k=25 N/m Displacement, x=65 cm To find force. 10- Force, F=75 N…

Q: An 8.0 g bullet is shot into a 3.0 kg block, at rest on a frictionless horizontal surface. The…

A: Given data: Mass of bullet is m=8 g=8 g××1 kg1000 g=0.008 kg. Mass of block is M = 3 kg.…

Q: A horizontal spring (with spring constant 180 N/m) is attached to the wall at the left, and a 10 Kg…

A: Given: The spring constant is 180 N/m. The mass of the object attached to the spring is 10 kg. The…

Q: A pendulum rope has a length of 2.50 meters and a bob mass of 3.00 kg. It the bob passes through the…

A: Length of the rope, Mass of the bob, Speed at the equilibrium position, Final speed,…

Q: In a room that is 2.44 m high, a spring (unstrained length = 0.30 m) hangs from the ceiling. A board…

Q: A block of mass M is dropped from rest on the spring asshown in the figure. The spring compresses a…

A: The energy possessed by an object which is in motion , with velocity v is known as the kinetic…

Q: A large spring with a spring constant of 15000 kg/sec2 is used to start a car on a roller coaster.…

A: The speed of the car when it leaves the spring is 12mv2=12kx2v=kx2m=15000 kg/s22.0 m21500 kg=6.32…

Q: Find the spring constant k for a spring if a force of 19 N stretches the spring 0.46_m.

A: Given data: Force (F) = 19 N Stretch in Spring (x) = 0.46 m Required: The spring constant (k)

Q: A 40.0 N force stretches a vertical spring 0.300 m.

A: Given :- Force =40N Vertical spring = 0.300m

Q: The cable of the 1800.0-kg elevator cab in the figure below snaps when the cab is at rest at the…

A: (given) Mass of the cable of elevator cab = 1800 kg Bottom distance (d) of elevator cab = 3.70…

Q: A 0.85kg mass vibrates according to the equation x= 0.75cos(7.2)t where x is in meters and t is in…

A: The given equation is x=0.75 cos7.2t ...... (I) The given equation is of the form,…

Q: A force of 50 N streches a certain spring by 20 cm. The spring constant is

A: Given data : Force that caused the stretching of spring, F = 50 N…

Q: A vertical spring has a spring constant of 5.2 N/m and a relaxed length of 2.45 m. A mass is…

A: Given data: Spring constant (k) = 5.2 N/m Relaxed length (L) = 2.45 m Stretched length (L') = 3.57 m…

Q: elastic potential energy stored in the spring

Q: During an experiment, a ball was thrown from the top of a building, 15.0 m in height from a spring.…

A: From the experiment, Kx = mg m = Kx/g Given, K = 185 N/m x = 2.75 m So, m = (185 x 2.75)/9.81…

Q: 21 A vertical spring 0.100 meter long Is a length of 0.119 meter when a 1.00-kilogram mass is…

A: Given Initial length of spring Li= 0.100 m Final length of spring Lf =0.119 m Mass attached M = 1 kg…

Q: A spring has a normal length of 10 inches. It has also been determined that its spring constant is…

Q: • If the spring shown is pulled by 400N force. The stretch (s) of the spring will be: lo k=200N/m…

Q: A load of 50N stretches a vertical spring by 0.15 m. What is the spring constant

Q: (ou have a light spring which obeys Hooke's law. This spring stretches 3.28 cm vertically when a…

Q: A 1.8 kg cart moving at 9.0 m/s [E] collides with a stationary 1.2 kg cart. The head-on collision is…

A: solution as

Q: A spring of stiffness 126 N/m (initially unstretched) is attached to a mass 6 kg on a frictionless…

A: m1=3 kgm2=6 kgv=5 m/sk=126 N/m

Q: A 2.40-kg block is dropped onto a spring and platform of negligible mass. the block is released a…

A: Spring constant is, 12kx2=mgh+xk=2mgh+xx2=22.40 kg9.8 m/s25.00 m+0.250 m0.250 m2=3951.36 N/m

Q: The natural length of a spring is 10cm. A force of 10N will stretch it t work done in stretching…

A: GivenNatural length of spring=10 cmForce, F=10 NAfter steching Toral length=12 cm

Q: An ideal spring obeys Hooke’s law: F = −ikx.A mass of m = 0.8 kg hung vertically fromthis spring…

A: The expression for the spring constant is,

Q: A mass of 30 kg is suspended on a spring scale. This stretches the spring by 35 cm. What elastic…

A: The spring force must be equal to the weight suspended. It is given by, kx=mg Here, k is the force…

Q: A 3.5 kg mass slides from a height of 27 m down a frictionless ramp into a spring. The spring…

A: The ramp is frictionless, so we can use the conservation of energy to answer the question.

Q: A spring on a horizontal surface can be stretched and held 0.4 m from its equilibrium position with…

Q: A 29.0 cm long spring is hung vertically from a ceiling and stretches to 37.5 cm when an 8.50 kg…

A: Given:Initial length of the spring = 29.5 cmWeight from the spring = 8.5 kg weightFinal length of…

Q: A stone is at rest on a spring, compressing the spring by 10.0 cm. The stone is pushed down a…

Q: A spring with a spring constant of 366 N/m is compressed so it contains 18.7392 joules of elastic…

Q: 10 N force made the spring stretched 5 cm longer than its original length, suspend a 2kg mass will…

A: Scenario - Spring stretches a certain length when a mass is suspended from it. Given : Initial force…

Concept explainers

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest. 

Question

A spring elongates by 1.5 cm because of a force of 15 N. Therefore the spring constant should be
O 1000.0 N/m
O 10.0 N/m
100.0 N/m
O 10,000.0 N/m

Expert Solution

Step 1

Given

Force F = 15 N

Elongation x = 1.5 cm = 1.5 × 10^-2m

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

A 1.50-kg box rests atop a massless vertical spring with k = 4250 N/m that has been compressed by 15.0 cm from its equilibrium position. The box is released and leaves the spring when it reaches its equilibrium position. What is the maximum height the box reaches above its original position?
An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 230 N. (a) What is the equivalent spring constant of the bow? (b) How much work does the archer do in pulling the bow? Figure P5.64
A cafeteria tray dispenser supports a stack of trays on a shelf that hangs from four identical spiral springs under tension, one near each corner of the shelf. Each tray is rectangular, 45.3 cm by 35.6 cm. 0.450 cm thick, and with mass 580 g. (a) Demonstrate that the top tray in the stack can always be at the same height above the floor, however many trays are in the dispenser, (b) Find the spring constant each spring should have for the dispenser to function in this convenient way. (c) Is any piece of data unnecessary for this determination?
A block of mass M rests on a table. It is fastened to the lower end of a light, vertical spring. The upper end of the spring is fastened to a block of mass m. The upper block is pushed down by an additional force 3mg, so the spring compression is 4mg/k. In this configuration, the upper block is released from rest. The spring lifts the lower block off the table. In terms of m, what is the greatest possible value for m?
A weight is connected to a spring that is suspended vertically from the ceiling. If the weight is displaced downward from its equilibrium position and released, it will oscillate up and down. (a) If air resistance is neglected, will the total mechanical energy of the system (weight plus Earth plus spring) be conserved? (b) How many forms of potential energy are there for this situation?
One type of toy car contains a spring that is compressed as the wheels are rolled backward along a surface. The spring remains compressed until the wheels are freed and the car is allowed to roll forward. Jose learns that if he rolls the car backward for a greater distance (up to a certain point), the car will go faster when he releases it. The spring compresses 1.00 cm for every 10.0 cm the car is rolled backward. a. Assuming the spring constant is 150.0 N/m, what is the elastic potential energy stored in the spring when Jose rolls the car backward 20.0 cm? b. What is the elastic potential energy stored in the spring when he rolls the car backward 30.0 cm? c. Explain the correlation between the results for parts (a) and (b) and Joses observations of different speeds.
A spring of spring constant k lies along an incline as shown in Figure P8.27. A block of mass m is attached to the spring. The spring compresses, and the block comes to rest as shown. Find an expression for the change in the Earthblockspring systems potential energy in terms of the parameters given in the figure.
The position of a particle attached to a vertical spring is given by y=(y0cost)j. The y axis points upward, y0 = 14.5 cm. and = 18.85 rad/s. Find the position of the particle at a. t = 0 and b. t = 9.0 s. Give your answers in centimeters.
When an 80.0kg man stands on a pogo stick, the spring is compressed 0.120 m. (a) What is the force constant of the spring? (b) Will the spring be compressed more when he hops down the read?
A light spring with spring constant 1 200 N/m is hung from an elevated support. From its lower end hangs a second light spring, which has spring constant 1 800 N/m. An object of mass 1.50 kg is hung at rest from the lower end of the second spring. (a) Find the total extension distance of the pair of springs. (b) Find the effective spring constant of the pair of springs as a system. We describe these springs as in series.
A spring 1.50 m long with force constant 475 N/m is hung from the ceiling of an elevator, and a block of mass 10.0 kg is attached to the bottom of the spring. (a) By how much is the spring stretched when the block is slowly lowered to its equilibrium point? (b) If the elevator subsequently accelerates upward at 2.00 m/s2, what is the position of the block, taking the equilibrium position found in part (a) as y = 0 and upwards as the positive y-direction. (c) If the elevator cable snaps during the acceleration, describe the subsequent motion of the block relative to the freely falling elevator. What is the amplitude of its motion?
A childs pogo stick (Fig. P7.69) stores energy in a spring with a force constant of 2.50 104 N/m. At position (x = 0.100 m), the spring compression is a maximum and the child is momentarily at rest. At position (x = 0), the spring is relaxed and the child is moving upward. At position , the child is again momentarily at rest at the top of the jump. The combined mass of child and pogo stick is 25.0 kg. Although the boy must lean forward to remain balanced, the angle is small, so lets assume the pogo stick is vertical. Also assume the boy does not bend his legs during the motion. (a) Calculate the total energy of the childstickEarth system, taking both gravitational and elastic potential energies as zero for x = 0. (b) Determine x. (c) Calculate the speed of the child at x = 0. (d) Determine the value of x for which the kinetic energy of the system is a maximum. (e) Calculate the childs maximum upward speed. Figure P7.69