A spring for which k=750 N/m, is suspended from a fixed support. A mass of 30 kg is attached to its lower end and the system is brought to rest. Find the position of the mass at time t=5 sec if a force equal to 20 sin 2t is applied to it.
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- The 10 N cylinder moves in a frictionless pipe. Spring constants are k1 = 150 N / m and k2 = 200 N / m. When the system is at rest, d = 0.5 m. (d is the distance from the right end of the arc k2). The system rotates around a fixed z-axis. Find the constant velocity of the cylinder for d = 0.20 m?The following mass-and-spring system has stiffness matrix K. The system is set in motion from rest (x1′(0)=x2′(0)=0)in its equilibrium position (x1'(0)=x2'(0)=0) with the given external forces F1(t)=0and F2(t)=540 cos 4t acting on the masses m1and m2,respectively. Find the resulting motion of the system and describe it as a superposition of oscillations at three different frequencies. m1 m2 k1 k2 k3 x1 x2 K= −k1+k2 k2 k2 −k2+k3 m1=1, m2=2; k1=1, k2=2, k3=2 Find the resulting motion of the system. x1(t) = x2(t) = (Type exact answers, using radicals as needed.)Cable AB is 0.5 m long. The unextended length of the spring is 0.4 m. When the 50-kg mass is suspended at B, the length of the spring increases to 0.45 m. What is the constant k of the spring?
- How much work is done by the force in the spring when the slender rod rotates from the position where e = 28" to the position where 0 = 63°? The spring has a stiffness of k = 157 N/m and is stretched by 0.21 m when e =0°. The spring is connected to a fixed wall, as well as the endpoint of the rod, as shown. The rod can rotate freely about the fixed pin support at O and AO remains horizontal during motion. Take 40= 1.77 m, which is also the length of the rod. Choose the correct answer. Hoeveel arbeid word deur die krag in die veer verrig wanneer die dun staaf vanaf die posisie waar 0 28 na die posisie waar 0 = 63° roteer? Die veer het 'n styfheid van k = 157 N/m en is 0.21 m uitgerek = wanneer 0 0°. Die veer is aan die vaste muur en die endpunt van die staaf verbind, soos aangetoon. Die staaf kan vrylik om die vaste penstut by O roteer en AO bly horisontaal tydens beweging. Neem AO 1.77 m, wat ook die lengte van die staaf is. Kies die korrekte antwoord. 0. Select one: O-271 Joule 244…2. Find the horizontal force P to start the motion of any part of the system of three blocks resting upon one another as shown. The weight of the blocks are W-300 KN, Ws= 100 KN and Wc =200 KN. Between A and B μ=0.30, between C and B, μ =0.20 and between C and the ground, p=0.10. 1 sni brod nog 02.0-4 B C 05.0-4 Solution: tamos quoy worla bre sosia asquar 005 300 en of jells400 N₁-300 F3 N-300- N₂=300 Assuming B and C will not move. F₁ = 300 (0.30) F₁ = 90 kN ne à bns A zelboß 1 P = 90 kN es ensla berb hebnu 02.0- y elin 05.0= q V in Celpris orllanimetsa MX 008 Assuming C will not move: al 1st F2=400 (0.20) = 80 kN OTE Bm ribirte F₂ vica Assuming the three blocks move: F3 = 0.10 (600) F3 = 60 kN P=60 KN Least force is 60 kN.A5 lbf weight is suspended froma vertical spring having a stiffness k = 50 lbf/ft. An impressed force F = 0.25 sin 8t lbę where t is in seconds is acting on the weight. Determine the equation of motion of the weight when it is pulled down 3 inches from the equilibrium position and released from rest.
- The torsional spring has a stiffness of 20 N-m/rad and is undeflected when the 3-kg uniform slender bar is in an upright position. If the bar is released from rest in the horizontal position shown, find its angular velocity as it passes the vertical position. Neglect friction effects. 4 Type here to search ThinkVision K - Pan Tab Cape Look Esc Q A Z G FT W S # ONDA 3 F2 E D A $ 4 R F 5 F4 T G XCVB 8 a Y H N P6 F6 U J M F7 K ( F8 F10 F11 +Backspace Enter T F12 Shift Print Screen SysRq Insert 0.5 m Scroll Lock Delete Home Break End Page Up Page Down Naam Lock K 37°F Cloudy Home Lenovo B 20The system shown below consists of a uniform disk D that has a mass of mp = 3.0 kg and a radius of r = 0.5 meters. The disk is connected by a massless cable to a block. The system is released from rest and the disk starts rolling without sliding with the angular acceleration of a = 24 rad in the clockwise direction. Determine the tension developed in the cable (in Newtons) at this instant. Consider 0 = 30° and g 10 * mpWhen the angle θ = 90 °, the cylinder BE starts with a vertical force (F = 3210 N) Newtons on the platform. Also, the box (box) is 200 kg and the angular velocity (ω) of body AB is 9 (rad / s). First, treat the box and platform as a single body to find the following: The magnitude of the reaction forces at points B and D. Box aG acceleration in the x and y direction. Second, having progressed earlier, only found the following for the platform: Reaction force from the box on the platform. Minimum symbol minimum A request of the consonant (μs) to disallow the box.
- The motorcycle in the figure has a mass of m1 kg and its center of mass is at G1. The mass of the driver is m2 kg and the center of mass is at G2. Since there is fs between the wheels and the asphalt, determine whether it is possible for the driver to lift the front wheel off the ground. Neglect the mass of the wheels and assume that the front wheel can spin freely. a=0.41 m b= 0.39 m c= 0.75 m d= 0.25 m e=0.58 m m1=120 kg m2= 77 kg fs=0.82The dynamic system is initially at rest. The rod has a mass of m=0.5kg and a length of L=1m. The CG of the rod is located at G, and the rod is rotated about the point O, a distance, h=0.25m, away from point G. When the rod from above is rotated at the vertical position (swing to 90 degrees counterclockwise), find: a. Angular velocity b. Reaction at OFial I The figure shows a body consist of two segments which are a rod AB and a disk with weights of 4-lb and 11-lb respectively. The body is attched with a spring. The roller 1 ft k = 8 lb/ft Datum at C allows the spring to remain vertical as the rod falls. B A The length of the unstretched spring is 0.85 ft. If the body is released from rest and rotates CW about point B, 1 ft 3 ft determine the following: (Assume the datum at point B) 0.25 ft 1. The potential energy of the spring when the body is horizontal. 2. The potential energy due to gravity when the body is horizontal. 3. The potential energy of the spring when the body is vertical. 4. The potential energy due to gravity when the body is vertical. 5. The angular velocity at the instant the body becomes vertical.