nd d = 0.8 mm. hear strain Yxy prad.
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- A tensile test was performed on a metal specimen with a diameter of 1 2 inch and a gage length (the length over which the elongation is measured) of 4 inches. The dam were plotted on a load-displacement graph. P vs. L. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P/L =1392 kips/in. What is the modulus of elasticity?Athin rectangular plate is uniformly deformed as shown. If L₁ = 0.125 in. and L₂ =0.135 in., determine the shear strain Yxy at P. 20 in. R 14 in. O -2460 μrad O -3070 μrad O -2800 μrad O -3390 μrad O -4670 μrad L₂ xConsider a point in a structural member that is subjected to plane stress. Normal and shear stress magnitudes acting on horizontal and vertical planes at the point are $x = 32 MPa, Sy= 79 MPa, and Sxy= 28 MPa. (a) Determine the principal stresses and the maximum in-plane shear stress acting at the point. (b) Show these stresses on an appropriate sketch (e.g., see Figure 12.15 or Figure 12.16) (c) Compute the absolute shear stress at the point. Sxy
- y 400 mm 4 mm B 200 mm A 6 mm The rectangular plate is subjected to the deformation shown by the dashed line. Determine the average shear stress in the plate if the shear modulus of the material is 2 MPa. Express your answer in kPa and round it to the nearest integer if necessary.Q5) The wooden block shown in Figure (4) will fail if the shear stress acting along the grain is (3.85 MPa). If the normal stress (d, = 2.8 MPa), determine the necessary compressive stress (a) that will cause failure. Figure (4)Shown is a composite plate joined together by rivets. The components consist of two tension bar plates that is ¾ X 4 inch and riveted together by two splice plates which is 0.8 X 6 inch. Each rivet has a diameter of 25.4 mm. Considering that the allowable stress for the tension bar plates and splice plates is σ=20.0 ksi, the allowable shear stress for the rivets is σ=25.0 ksi and the allowable bearing stress on the rivets and splice plates is σ=25.0 ksi. What will be the maximum permissible load P such that none of the allowable stresses will be exceeded?
- Part A Determine average normal stress. (Figure 1) Express your answer with the appropriate units. Javg = Part B μA Submit Request Answer Value σ1,02= 20 MPa IVD ΑΣΦ11 Units vec ww Determine the principal stress. Enter your answers numerically separated by a comma. ? 80 MPa 30 MPa www MPaThe center post B of the assembly has an original length of 124.7 mm, whereas postsA and C have a length of 125 mm. If the caps on the top and bottom can beconsidered rigid, determine the average normal stress in each post. The posts aremade of aluminum and have a cross-sectional area of 400 mm Eal = 70 GPa. Detailed solution pls. Thank you!A small aluminum alloy [E = 73 GPa] teeshape is used as a simply supported beam as shown. For this beam, a = 150 mm. The cross- sectional dimensions of the teeshape are b = 25 mm, d= 38 mm, and t=7 mm. After loads are applied to the beam at B, C, and D, a compressive normal strain of 490cis measured from a strain gage located at c= 9 rmm below the topmost edge of the tee stem at section 1-1. What is the applied load P? 3P Strain gage d a a H Answer: P = i
- 1. Two A36 16mm thick steel plates are connected by four rivets shown. 1:11 Pu a. Calculate design strength in KN considering tension failure on gross section yielding. b. Calculate design strength in KN considering tension failure on net section fracture. c. Calculate design strength in KN considering block shear rupture. f. Calculate the ultimate safe load "P" in KN. Given: 500 X =175mm Rivet Dia.=20mm Y=200mm Fy=248Mpa Fu=40 Mpa Bolt Dia.=22mmGIVEN: Solid alumınum bar shown: 4 in. by4 in. E = 10 x 10° psi oy = 36 ksi 4000 2000 1b 4000 16 B 12' REQ’D: A) Load in each section of the bar (state whether C or T) PAB = Pac PCD = B) Maximum axial stress in the bar. In which section does this occur? C) Final length of the baridity modulus doengro 17. A 12 mm thick plate is conected to two 8 mm thick plates, on either side through a 16 mm diameter power driven field rivet as shown in the figure below. Assuming permissible shear stress as 90 MPa and permissible bearing stress as 270 MPa in the rivet, the rivet value of the joint is as aeqml 19WOL to da odt ons aasmos m noienet ni mioj по djiw YIVO P/24 F 12mm ↑ P/2 00 8mm 8mm