(a) To appreciate the human ear’s twelve order of magnitude (1012) span from barely audible to the pain threshold, consider the following. Suppose an equivalently dynamic instrument were designed to measure distances. Taking the lower limit of the instrument to be 1.00 mm, what would be the largest distance measurable? (b) To provide a perspective for the human ear’s frequency sensitivity range (audible frequency extremes differ by 103 ), consider a speedometer with a similar speed range. If the speedometer’s maximum speed reading is 90.0 mi/h, what is the smallest finite speed that it could register?

icon
Related questions
Question

(a) To appreciate the human ear’s twelve order of magnitude (1012) span from barely audible to the pain threshold, consider the following. Suppose an equivalently dynamic instrument were designed to measure distances. Taking the lower limit of the instrument to be 1.00 mm, what would be the largest distance measurable? (b) To provide a perspective for the human ear’s frequency sensitivity range (audible frequency extremes differ by 103 ), consider a speedometer with a similar speed range. If the speedometer’s maximum speed reading is 90.0 mi/h, what is the smallest finite speed that it could register?

Expert Solution
Step 1

Fundamental frequency in an organ pipe closed at one end is,

f0=v4l

Here, v is the velocity and l is the length.

As, v=v01+t546

Here, v0 is the speed of sound in air at °C and, t is the temperature in °C

So, the length can be calculated as,

l=v4f0=vo1+t5464f0=331.5 m/s1+185464256 Hz=0.33 m

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer