A trait in garden peas involves the curling of leaves. A two-factorcross was made by crossing a plant with yellow pods and curlingleaves to a wild-type plant with green pods and normal leaves. AllF1 offspring had green pods and normal leaves. The F1 plants werethen crossed to plants with yellow pods and curling leaves. Thefollowing results were obtained: 117 green pods, normal leaves115 yellow pods, curling leaves78 green pods, curling leaves80 yellow pods, normal leavesA. Conduct a chi square analysis to determine if these two genesare linked.B. If they are linked, calculate the map distance between the twogenes. How accurate do you think this calculated distance is?

A trait in garden peas involves the curling of leaves. A two-factorcross was made by crossing a plant with yellow pods and curlingleaves to a wild-type plant with green pods and normal leaves. AllF1 offspring had green pods and normal leaves. The F1 plants werethen crossed to plants with yellow pods and curling leaves. Thefollowing results were obtained: 117 green pods, normal leaves115 yellow pods, curling leaves78 green pods, curling leaves80 yellow pods, normal leavesA. Conduct a chi square analysis to determine if these two genesare linked.B. If they are linked, calculate the map distance between the twogenes. How accurate do you think this calculated distance is?

Name: A trait in garden peas involves the curling of leaves. A two-factorcro
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: A trait in garden peas involves the curling of leaves. A two-factorcross was made by crossing a plant with yellow pods and curlingleaves to a wild-type plant with green pods and normal leaves. AllF1 offspring had green pods and normal leaves. The F1

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 2ACQ: Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are...

See similar textbooks

Similar questions

Two pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64
Summer squash exist in long, spherical, or disk shapes. When atrue-breeding long-shaped strain was crossed to a true-breedingdisk-shaped strain, all of the F1 offspring were disk-shaped. Whenthe F1 offspring were allowed to self-fertilize, the F2 generationconsisted of a ratio of 9 disk-shaped to 6 round-shaped to 1 longshaped. Assuming the shape of summer squash is governed by twodifferent genes, with each gene existing in two alleles, propose amechanism to account for this 9:6:1 ratio
A cross was made between two strains of plants that are agriculturallyimportant. One strain was disease-resistant but herbicide-sensitive;the other strain was disease-sensitive but herbicide-resistant. Aplant breeder crossed the two plants and then allowed the F1 generation to self-fertilize. The following data were obtained:F1 generation: All offspring are disease-sensitive andherbicide-resistantF2 generation: 157 disease-sensitive, herbicide-resistant57 disease-sensitive, herbicide-sensitive54 disease-resistant, herbicide-resistant20 disease-resistant, herbicide-sensitiveTotal: 288Formulate a hypothesis that you think is consistent with the observeddata. Test the goodness of fit between the data and your hypothesisusing a chi square test. Explain what the chi square results mean
In four o’clock plants, many flower colors are observed. In a crossinvolving two true-breeding strains, one crimson and the otherwhite, all of the F1 generation were rose color. In the F2, four newphenotypes appeared along with the P1 and F1 parental colors.The following ratio was obtained: 1/16 crimson2/16 orange1/16 yellow2/16 magenta4/16 rose2/16 pale yellow4/16 white Propose an explanation for the inheritance of these flowercolors.
A homozygous variety of opium poppy (Papaver somniferum Laciniatum) with lacerate leaves was crossed with another homozygous variety with normal leaves. All the F₁ had lacerate leaves (jagged-edged leaves). Two F₁ plants were crossed to produce the F2. Of the F2, 249 had lacerate leaves and 16 had normal leaves. How are lacerate leaves determined in the opium poppy? two genes, with a dominant allele at both loci two genes, where one allele at a single locus is recessive lethal one gene, with codominant alleles at a single locus two genes, with a dominant allele at either or both loci Give genotypes for all the plants in the P, F₁, and F2 generations. Some generations will have more than one genotype. P F₁ F₂ (lacerate) F₂ (normal) aabb A_B_ Answer Bank aaB AaBb A_bb AABB
Two genes in tomatoes are 61 mu apart; normal fruit (F) isdominant to fasciated fruit (f ), and normal number of leaves(Lf ) is dominant to leafy (lf ). A true-breeding plant with anormal number of leaves and fruit was crossed to a leafy plantwith fasciated fruit. The F1 offspring were then crossed to leafyplants with fasciated fruit. If this cross produced 600 offspring,what are the expected numbers of plants in each of the fourpossible categories: normal leaf number, normal fruit; normalleaf number, fasciated fruit; leafy, normal fruit; and leafy,fasciated fruit?
A variety of opium poppy (Papaver somniferum L.) with lacerate leaves was crossed with a variety that has normal leaves. All the F1 had lacerate leaves. Two F1 plants were interbred to produce the F2. Of the F2, 249 had lacerate leaves and 16 had normal leaves. Give genotypes for all the plants in the P, F1, and F2 generations. Explain how lacerate leaves are determined in the opium poppy.
A true-breeding pea plant with round and green seeds was crossedto a true-breeding plant with wrinkled and yellow seeds. Roundand yellow seeds are the dominant traits. The F1 plants wereallowed to self-fertilize. What are the following probabilities forthe F2 generation?A. An F2 plant with wrinkled, yellow seeds.B. Three out of three F2 plants with round, yellow seeds.C. Five F2 plants in the following order: two have round, yellowseeds; one has round, green seeds; and two have wrinkled,green seeds.D. An F2 plant will not have round, yellow seeds
In the garden pea, orange pods (o) are recessive to green pods (+), and sensitivityto pea mosaic virus (v) is recessive to resistance to the virus (+). A plant withorange pods and sensitivity to the virus was crossed to a true-breeding plant withgreen pods and resistance to the virus. The F1 progeny were then test-crossed toplants with orange pods and sensitivity to the virus with the following results:160 orange pods, virus sensitive 36 orange pods, virus resistant165 green pods, virus resistant 39 green pods, virus sensitive 1. What are the gamete frequencies of the recombinants and non-recombinants? 2. What are the expected frequencies of the recombinant and non-recombinantgenotypes?
In the garden pea, orange pods (o) are recessive to green pods (+), and sensitivity to pea mosaic virus (v) is recessive to resistance to the virus (+). A plant with orange pods and sensitivity to the virus was crossed to a true-breeding plant with green pods and resistance to the virus. The F1 progeny were then test-crossed to plants with orange pods and sensitivity to the virus with the following results: 160 orange pods, virus sensitive 36 orange pods, virus resistant 165 green pods, virus resistant 39 green pods, virus sensitive A goodness of fit analysis for the operative genetic mechanism behind these obtained results will result to a X2 value of ____ which is (below, above) the alpha value, and interpreted as (significant, not significant). Hence the hypothesis that the data is due to (dihybrid self-cross, linkage, epistasis) is (accepted, not accepted). Express answer in decimal form. Significant # of decimal…
In the tomato, three genes are linked on the same chromosome. Tallis dominant to dwarf, skin that is smooth is dominant to skin that ispeachy, and fruit with a normal rounded tomato shape is dominantto oblate (flattened) shape. A plant that is true-breeding for thedominant traits was crossed to a dwarf plant with peachy skin andoblate fruit. The F1 plants were then testcrossed to dwarf plants withpeachy skin and oblate fruit. The following results were obtained: 151 tall, smooth, normal33 tall, smooth, oblate11 tall, peach, oblate2 tall, peach, normal155 dwarf, peach, oblate29 dwarf, peach, normal12 dwarf, smooth, normal0 dwarf, smooth, oblate Construct a genetic map that shows the order of these three genesand the distances between them?
In corn, the cross WW ee FF × ww EE ff is made. The three loci are linked as follows:Assume no interference. a. If the F1 is testcrossed, what proportion of progeny will be ww ee ff? b. If the F1 is selfed, what proportion of progeny will be ww ee ff?