A uniformly charged insulating spherical shell of inner radius R1 = 4.0 cm and outer radiusR2 = 6.0 cm with a volume charge density p = -15.0 µC/m³ isshown. There is a point charge Q = 20 nč at the center.Note: The volume of a sphere is V =r³R1 = 4.0 cma) Calculate the total charge, Q, in the spherical shell.Q = +20.0 nCR2 = 6.0 cmb) Calculate the electric field at r = 3.0 cm.c) Calculate the electric field at r = 5.0 cm.p = -15.0 µC/m3d) Calculate the electric field at r = 10.0 cm.

Solving only 3 parts due to time constraint. Given: The inner radius of the shell is 4.0 cm. The…

A uniformly charged insulating spherical shell of inner radius R1 = 4.0 cm and outer radius R2 = 6.0 cm with a volume charge density p = -15.0 µC/m³ is shown. There is a point charge Q = 20 nC at the center. Note: The volume of a sphere is V = nr3 R1 = 4.0 cm a) Calculate the total charge, Q, in the spherical shell. Q = +20.0 nC R2 = 6.0 cm b) Calculate the electric field at r= 3.0 cm. c) Calculate the electric field at r = 5.0 cm. p = -15.0 µC/m³

A uniformly charged insulating spherical shell of inner radius R1 = 4.0 cm and outer radius R2 = 6.0 cm with a volume charge density p = -15.0 µC/m³ is shown. There is a point charge Q = 20 nC at the center. Note: The volume of a sphere is V = nr3 R1 = 4.0 cm a) Calculate the total charge, Q, in the spherical shell. Q = +20.0 nC R2 = 6.0 cm b) Calculate the electric field at r= 3.0 cm. c) Calculate the electric field at r = 5.0 cm. p = -15.0 µC/m³

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter6: Gauss's Law

Section: Chapter Questions

Problem 69P: The surface charge density on a long straight metallic pipe is . What is the electric field outside...

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