A wire carries a steady current of 2.40 A 75-cm-long straight section of the wire lies along the x-axis within a uniform magnetic field of magnitude B=1.60 T in the positive z-direction. If the current is in the +x direction, what is the magnetic force on the section of wire?
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- 1. Consider a long, thick current-carrying wire with radius R. A. Find the magnetic field at z=R from the wire. B. How much current is enclosed (Ienc) at 0 < z <R? Note: the answers are in formula form.a. A copper wire carries a current of 135 A to an electroplating tank. Find the magnetic field caused by a 1.3-cm segment of this wire at a point 1.5 m away from it, if a point is on a line at 40 deg to the segment. b. Two straight , parallel , superconducting wires 6.5 mm apart carry equal currents of 17,000 A in opposite direction. Calculate the force per length.1. Take e/m to be the accepted value of 1.76-10¹¹ C/kg. For a plate voltage of 100 volts and a circular beam of radius 3.0 cm, what would you expect the required magnetic field B to be? Assume that the above magnetic field is produced by two Helmholtz coils, and assume that each coil has 119 turns, a radius of 106 mm, and a separation of 106 mm. What cur- rent I is required to achieve the expected magnetic field?
- 2. A conducting structure seen in figure carries uniform and direct current I is inside a magnetic field with B = Be,. Find the total force acting on this structure by using Lorentz force law. After obtaining general expression, use I = 2 A; B = 0.3 T; AB = TD = 20 cm; R= 10 cm to calculate the force. y O z, B R В C A. DPlease help me solve the following. A 5.6 uc particle with a mass of .00092 kg is going 775 m/s when it is exposed to a magnetic field and begins moving in a circle. the magnetic force on the particle is .5 N. Determine the b-field and the radius of the circle.Solve c & d only. Use the following constants if necessary. Coulomb constant, k = 8.987×10^9 N⋅m^2/C^2 . Vacuum permitivity, ϵ0= 8.854×10^−12 F/m. Magnetic Permeability of vacuum, μ0 = 12.566370614356×10^−7 H/m. Magnitude of the Charge of one electron, e = −1.60217662×10^−19 C. Mass of one electron, m_e = 9.10938356×10^−31 kg. Unless specified otherwise, each symbol carries their usual meaning. For example, μC means microcoulomb .
- Please solve correctly. Use the following constants if necessary. Coulomb constant, k = 8.987×10^9 N⋅m^2/C^2 . Vacuum permitivity, ϵ0= 8.854×10^−12 F/m. Magnetic Permeability of vacuum, μ0 = 12.566370614356×10^−7 H/m. Magnitude of the Charge of one electron, e = −1.60217662×10^−19 C. Mass of one electron, m_e = 9.10938356×10^−31 kg. Unless specified otherwise, each symbol carries their usual meaning. For example, μC means microcoulomb .A beam of protons is directed in a straight line along the +z direction through a region of space in which there are crossed electric and magnetic fields. The electric field is 450 V/m in the -y direction and the protons move at a constant speed of 10^5 m/s. 1)What must be the magnitude of the magnetic field such that the beam of protons continues along its straight-line trajectory? (Express your answer using two significant figures.)a. Design a circular conductor in XY plane to generate amagnetic dipole moment 100 mA meter 2 square along Zaxis.b. How much magnetic flux density can be obtained from thisconductor along Y axis at a distance of 10 meter? Usevalue of permeability of space 4πx 10 -7 .
- An electron enters a uniform magnetic field B = 0.31 T at a 40 angle to B⃗ 1.Determine the radius rr and pitch pp (distance between loops) of the electron's helical path assuming its speed is 3.0×106 m/sm/s . See the figure. 2.what is p?An electron ( me = 9.11X10-31 kg. q=1.6X10-91 C) moves in a circular %3D path perpendicular to a uniform magnetic field with a magnitude of 7.2 mT. If the speed of the electron is 1.50 X107 m/s, determine the radius of the circular path ( in units of cm). Select one: O A. 1.46 В. 1.19 O C. 0.04 O D. 0.63 O E. 1.74Figure 1: CRT with coils in Helmholtz configuration. The hot cathode emits electrons which are then accelerated through potential difference Vacc. When the electrons enter the magnetic field B, which is perpendicular to their velocity, they move on a circular path with radius r. The magnetic field is due to coils in Helmholtz configuration (2 coils separated distance that equals their radius). The magnetic field due to one of the coils with radius R, at a point on the axis distance z away from the center of the coil, was found using the Biot-Savart law: HOIR?N B1 2(R2 + z2)ž